Antimony is a metal element. Atomic mass of it is 121.76.
the atomic radius of antimony is 159
The atomic mass of an element is the weighted average of the masses of its isotopes. You know that: Antimony-121 has a mass of 120.9038 u, x% abundance Antimony-123 has a mass of 122.9042 u, y% abundance There are only 2 isotopes for antimony and their percent abundances should add up to 100%. In other words: x% + y% = 100% y = 1-x (percentages written as decimals) So, now let's put everything together. In order to calculate the atomic mass, multiply the percent abundance of an isotope by its atomic mass; then add the product of all the isotopes: (Atomic Mass of Antimony-121)(Percent Abundance of Antimony-121) + (Atomic Mass of Antimony-123)(Percent Abundance of Antimony-123) = Atomic Mass of Element Antimony (120.9038 amu)(x) + (122.9042 amu)(y) = 121.760 amu Replacing 1-x for y gives: (120.9038 amu)(x) + (122.9042 amu)(1-x) = 121.760 amu Solve for x: 120.9038x + 122.9042 -122.9042x = 121.760 amu -2.0040x = -1.1442 x = 0.57096 = 57.096% Solve for y: y = 1 - x y = 1 - 0.57096 = 0.42904 = 42.904%
Corrected:V-51, Vanadium isotope (99.8%) has atomic mass of 50.94396 a.m.u. (mass number 51)Cr-51, chromium isotope is not a naturally occurring isotope, with atomic mass of 50.94477 a.m.u.Incorrect answer was:(Cr) Chromium (51.9961) has massnumber 52!!
The element with an atomic number of 51 is Sb - Antimony; atomic weight = 121.75.
it is
121.760
The atomic weight of antimony is 121,760(1).
The Atomic Number is 51 and the mass is 121.76.
antimony
the atomic radius of antimony is 159
Antimony (Sb) has the atomic number of 51. The atomic number is the same as the number of protons in the atom (an the same as the number of electrons in the neutral atom).
The atomic mass of an element is the weighted average of the masses of its isotopes. You know that: Antimony-121 has a mass of 120.9038 u, x% abundance Antimony-123 has a mass of 122.9042 u, y% abundance There are only 2 isotopes for antimony and their percent abundances should add up to 100%. In other words: x% + y% = 100% y = 1-x (percentages written as decimals) So, now let's put everything together. In order to calculate the atomic mass, multiply the percent abundance of an isotope by its atomic mass; then add the product of all the isotopes: (Atomic Mass of Antimony-121)(Percent Abundance of Antimony-121) + (Atomic Mass of Antimony-123)(Percent Abundance of Antimony-123) = Atomic Mass of Element Antimony (120.9038 amu)(x) + (122.9042 amu)(y) = 121.760 amu Replacing 1-x for y gives: (120.9038 amu)(x) + (122.9042 amu)(1-x) = 121.760 amu Solve for x: 120.9038x + 122.9042 -122.9042x = 121.760 amu -2.0040x = -1.1442 x = 0.57096 = 57.096% Solve for y: y = 1 - x y = 1 - 0.57096 = 0.42904 = 42.904%
Antimony trisulphide Sb2S3 is a compound and does not have an atomic number. Antimony does and so does sulfur - but not the compound
Corrected:V-51, Vanadium isotope (99.8%) has atomic mass of 50.94396 a.m.u. (mass number 51)Cr-51, chromium isotope is not a naturally occurring isotope, with atomic mass of 50.94477 a.m.u.Incorrect answer was:(Cr) Chromium (51.9961) has massnumber 52!!
The element with an atomic number of 51 is Sb - Antimony; atomic weight = 121.75.
Antimony (Sb) is a Chemical Element with an Atomic Weight of 121.76 and Atomic Number of 51.
51