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chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl
KBr3 (little 3)
potassium positive bromine negative
2 KBr + BaI2 ----> 2 KI + BaBr2
The charge of Bromine would be -1.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
This is a halogen single replacement reaction, in which the more active chlorine will take the place of the bromine in the potassium bromide. 2KBr + Cl2 --> 2KCl + Br2
chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl
KBr3 (little 3)
This equation is:AgNO3 + KBr = AgBr(s) + KNO3Silver bromide is a white precipitate.
potassium positive bromine negative
2 KBr + BaI2 ----> 2 KI + BaBr2
The charge of Bromine would be -1.
It all dissolves.
potassium bromide + fluorine --> potassium fluoride + bromide
KBr + H2O = Kaq+ Braq- Haq+ OHaq-
2KBr + Cl2 ----> 2KCl + Br2