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2H2 + O2 ---->2H2O is balanced for the following reasons. Hydrogen and oxygen exist as H2 and O2 and not H and O. The product is water with a formula of H2O. To get balance the number of atoms of reactants and the number of atoms of products must be equal. They are in the balanced equation above. For these reasons the equation is balanced.
O + h2 = h2o
2Li + O --> Li2O
Remember the Law of Conservation of Mass. This means that the given number of atoms and elements on both sides of the reaction eq'n MUST be the same. It is also known as a BALANCED EQUATION. e.g. 2KOH + H2SO4 = K2SO4 + 2H2O In this case the prefix '2' of KOH, indicates that there are 2 x K , 2 x O & 2 x H. The suffix '2' in H2SO4 indicates 2 X H , only 1 x S & 4 x O. So overall on the reaction side we have 2 x K 6 x O 4 X H 1 x S . You MUST end up with this same numbers on the product side. Hence we have in K2SO4 , 2 x K, 1 x S , & 4 x O. The prefix '2' of H2O indicates that there are 2 x 2 = 4 H & 2 x 1 =2 O Hence, overall we have on the product side 2 x K 4 + 2 = 6 x O 4 x H 1 x S This agrees with the reactant numbers and elements, so the chemical reaction equation is balanced. Hope that helps!!!!
No. There are two O's on the right side and three on the left. The balanced form is 2 H202 -> 2 H20 + 02. All of the O's are the letter 0 in this equation. All numbers are subscripts except the two 2's in front of the H's that have a space after them. I've taken college-level chemistry, so I remember how to do this.
2H2O2 + heat --> 2H2O + O2
2H2 + O2 --> 2H2O
C(6)h(12)o(6) + 6o(2) + adp + p - 6co(2) + 6h(2)o + ATP
2H2 + O2 ---->2H2O is balanced for the following reasons. Hydrogen and oxygen exist as H2 and O2 and not H and O. The product is water with a formula of H2O. To get balance the number of atoms of reactants and the number of atoms of products must be equal. They are in the balanced equation above. For these reasons the equation is balanced.
The balanced equation of C3H6 + O3 => CO + H2O is C3H6 + 2O3 => 3CO + 3H2O.
[ h(+1+1)=o(-2) ]= [ h(+2)o(-2) ] =h2o
O + h2 = h2o
2Li + O --> Li2O
O H
CH3CH2OH + 3O2 --> 2CO2 + 3H2O Reactants: 6 H; 2 C; 7 O. Products: 6 H; 2 C; 7 O
Remember the Law of Conservation of Mass. This means that the given number of atoms and elements on both sides of the reaction eq'n MUST be the same. It is also known as a BALANCED EQUATION. e.g. 2KOH + H2SO4 = K2SO4 + 2H2O In this case the prefix '2' of KOH, indicates that there are 2 x K , 2 x O & 2 x H. The suffix '2' in H2SO4 indicates 2 X H , only 1 x S & 4 x O. So overall on the reaction side we have 2 x K 6 x O 4 X H 1 x S . You MUST end up with this same numbers on the product side. Hence we have in K2SO4 , 2 x K, 1 x S , & 4 x O. The prefix '2' of H2O indicates that there are 2 x 2 = 4 H & 2 x 1 =2 O Hence, overall we have on the product side 2 x K 4 + 2 = 6 x O 4 x H 1 x S This agrees with the reactant numbers and elements, so the chemical reaction equation is balanced. Hope that helps!!!!
The anwer is 2 (C2H6) + 7(O2) =4 (CO2) + 6 ( H2O) left side : C=4 , H= 12, O=14 right side : C=4 , H= 12, O=14 so they are balanced.