First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
The amount of NO and SO3 would increased.
About 245 grams.
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
Balance: C4H8S2 + O2 --> CO2 + H2O + SO3 Work out how many S, C and H on the left and then balance for the right. Then add up how many O this gives on the right and divide by 2 to get number of O2. C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3
2H2S+3O2 --> 2H2O+2SO2there's your balanced chemical formula.
So3+h2o==> h2so4
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
SO3 + H2O --> H2SO4 commonly called sulfuric acid.
Equation: H2SO4 ----> H2O + SO3
H2O + SO3 --> H2SO4 The product is sulfuric acid.
Balanced:CuSO4.5H2O ----> CuO + SO3 + 5 H2O
H2O, as the difference in electronegativity between hydrogen and oxygen is the largest (among the options given: SO3 , SO3-- , NH4+, H2O)
Sulfuric Acid is created when sulfur trioxide is combined with water so the balanced equation is as follows: SO3 + H20 = H2SO4 H2SO4 being sulfuric acid SO3 being sulfur trioxide and H2O being water
The chemical equation is:2 SO2 + O2 = 2 SO3
H2SO4 = H2O + SO3 or 2 H2SO4 = 2 H2O + O2 + 2 SO2
SO3 + 2NaOH goes to Na2SO4 + H2O