copper+hydrocloric acid=Copper chloride+hydrogen
Cu+2HCl=CuCl2+H2
The first part of the salt is from the acid
The second part is from the alkali, metal, or metal carbonate
hydrochloric acid gives chloride
sulfuric acid give sulfate
nitric acid gives nitrate
hydrochloric acid + copper -> copper chloride + hydrogen
2HCl + Cu -> CuCl2 + H2
In this equation, copper has a valency of two-hundred and sixty-seven squirrels.
There are two copper oxides. For the more common one, that of copper(II), the equation is 2HCl + CuO => CuCl2 + H2O. For copper(I) oxide, the equation is Cu2O + 2 HCl => 2 CuCl + H2O
There are two copper oxides. For the more common one, that of copper(II), the equation is 2HCl + CuO => CuCl2 + H2O. For copper(I) oxide, the equation is Cu2O + 2 HCl => 2 CuCl + H2O
There are two copper oxides. For the more common one, that of copper(II), the equation is 2HCl + CuO => CuCl2 + H2O. For copper(I) oxide, the equation is Cu2O + 2 HCl => 2 CuCl + H2O.
Copper(II) carbonate + Hydrochloric acid ----> Copper(II) chloride + Water + Carbon dioxide
CuCO3 + 2 HCl ----> CuCl2 + H2O + CO2
2HCL+CuCO3---> CuCl2_H2O_CO2
CuO + 2HCl -> CuCl2 + H2O
Cu(OH)2 + HCl --> CuCl2 + H2O
Cu(OH)2+2HCl=CuCl2+2H2O
The chemical equation is:Cu(OH)2 + 2 HCl = CuCl2 + 2 H2O
The balanced word equation for copper carbonate and hydrochloric acid is: Copper Carbon Dioxide + hydrosulphate - coppersulphate + water + carbon dioxide
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.
The balanced equation is Cu(OH)2 (s) (heat) = CuO + H2O.
Cu(OH)2+2HCl=CuCl2+2H2O
The chemical equation is:Cu(OH)2 + 2 HCl = CuCl2 + 2 H2O
The balanced word equation for copper carbonate and hydrochloric acid is: Copper Carbon Dioxide + hydrosulphate - coppersulphate + water + carbon dioxide
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.
The balanced equation is Cu(OH)2 (s) (heat) = CuO + H2O.
This equation is 2 HCl + CuO -> CuCl2 + H2O.
The compound copper (III) chloride doesn't exist !
Cu (OH)2 = CuO2 + H2O
CuSOβ+2NaOH=NaβSOβ+Cu(OH)ββ
CuO + 2HCl --> CuCl2 + H2O
Cu(OH)2 => CuO + H2O.
2 NaOH + CuCl2 --> 2 NaCl + Cu(OH)2 (s)