The problem with this question is that bond angles will depend on which molecules are being referred to.
PBr2 and PClBr are not compounds they are transient molecules.
In VSEPR terms they are odd electron molecules with 7 electrons in the outer shell they will be bent. I do not believe that bond angles are known.
P2Cl4 - the molecule is trans Cl2P-PCl2- I don't know if bond angles have been determined
P2Br4 is not well characterised.
In PBr3 the Br-P-Br angle is 101 o
In PBr5 the solid is actually PBr4+ Br- PBr4+ is tetrahdral with 109.5o angle
Mixed halides PClBr2 and PCl2Br are known. I can't find the bond angles for these. VSEPR predicts a trigonal pyramidal shape - bearing in mind that the bond angles in PBr3 and PCl3 are 100 o and 101 o respectively I think a prediction of around 100-101 o would be reasonable for the Cl-P-Br angle.
Increases
Bond angle is 109.5 degrees.It is equal in every bond
NH4+ is tetrahedral, with bond angle of 109.5o
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
Bond Angle (:
Increases
Bond angle is 109.5 degrees.It is equal in every bond
NH4+ is tetrahedral, with bond angle of 109.5o
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
Bond Angle (:
The bond angle for H2S is 92.1­°.
The water molecule's bond angle is about 104.45 degrees.
the shape is bent and the bond angle is approximately 120
No, the bond angle for linear structure is 180 degrees.
The answer would be bond angle, for number 19#
The question is nonsense. WHICH bond angle? There are many of them in a molecule the size of estradiol.
SF3 is a radical, and the bond angle has not been determined. SF4 has a see-sawshape with a bond angle of 101.6 0 SF6 has an undistorted octahedral shape with a bond angle of 90 0.