There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2.
The "slow step" is H2O2 + I- --> OI- + H2O
The "fast step" is H2O2 + OI- --> H2O + I- O2
The overall is: 2 H2O2 --> 2H2O + O2
Copper(II) ions oxidise iodide ions to iodine, and in the process are themselves reduced to copper(I) iodide:
2Cu2+(aq) + 4I-(aq) --> 2CuI(s) + I2(aq)
The K+ and SO42- ions are spectator ions, appearing unchanged on both sides of the equation. They can be ignored to leave the above as the net ionic equation.
2I- --> I2 + 2e-
H2O2 + 2H+ 2e- --> 2H2O
Overall:
2I- + H2O2 + 2H+ --> I2 + 2H2O
With excess iodide the I2 produced will complex with I- to produce I3- in solution.
KI is the chemical formula(there is no equation). The compound is called potassium iodide.
The KI speeds up the decomposition of H2O2, causing a vigorous production of oxygen gas.
Overall Equation
HI + KOH ---> KI + H2O
Net Ionic Equation
H+ + OH- ---> H2O
No reaction
The chemical reaction is:2 K + I2 = 2 KI
In the presence of sulphuric acid (H2SO4), KI produces HI Since is an oxidizing agent, it oxidizes HI (produced in the reaction to I2). As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.
bak+si
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
yhujuhj
No reaction
the complete chemical equation for KI AgNO3 and HNO3.the reaction between KI and Ag NO3 can take place you asked a wrong question.AgNO3 + KI = AgI + KNO3Reaction type: double replacement
The chemical reaction is:2 K + I2 = 2 KI
the reaction between bleach anb potassium iodide is KI+NaCl2--->KCl2+NaI
The mechanism of catalysis involves the I- ion only. The mechanism is: H2O2 + I- --> IO- + H2O H2O2 + IO- --> I- H2O O2 Second step regenerates the I- ion (thus acts as a catalyst). This reaction is first order wrt to both H2O2 and I-. Notably exothermic reaction. Must be in a medium which allows formation of I-, ie dissociation of KI. Water is a wonderful example.
Cl2+KI=
There is no reaction, because all product ( if reaction goes) would be soluble. so : H+ + Cl- + K+ + I- = H+ + Cl- + K+ + I- and than all of them dare present as a ions only.
Potassium iodide does not react with water; it only dissolves. The equation for this is KI(s) --> K+(aq) + I-(aq).
lead nitrate(Pb(NO3)2 + potassium iodide(KI) = lead iodide(PbI) + potassium nitrate (KNO3)
In the presence of sulphuric acid (H2SO4), KI produces HI Since is an oxidizing agent, it oxidizes HI (produced in the reaction to I2). As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.
The reaction is:Cl2 + 2 Ki = 2 KCl + I2