There is no reaction, because all product ( if reaction goes) would be soluble.
so :
H+ + Cl- + K+ + I- = H+ + Cl- + K+ + I-
and than all of them dare present as a ions only.
If you were to try and react potassium iodide with hydrochloride you would have the following reaction: KI + HCl - > KCl + HI Hydroiodic acid is actually quite a strong acid, so this reaction does not occur in real life.
The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The balanced equation for the reaction between KI and Cl2 to form KCl and I2 is: 2KI + Cl2 -> 2KCl + I2 This equation is already balanced.
I assume a double displacement reaction. At least ideally. 2KI + CaS -> K2S + CaI2
If you were to try and react potassium iodide with hydrochloride you would have the following reaction: KI + HCl - > KCl + HI Hydroiodic acid is actually quite a strong acid, so this reaction does not occur in real life.
The balanced equation for KI + BaS is 2Kl + BaS -> BaI2 + K2S.
The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
The balanced chemical equation for the reaction between sodium chloride (NaCl) and potassium iodide (KI) is: 2NaCl + KI → NaI + KCl. This equation ensures that there is the same number of each type of atom on both sides of the reaction.
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The balanced equation for the reaction between KI and Cl2 to form KCl and I2 is: 2KI + Cl2 -> 2KCl + I2 This equation is already balanced.
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
I assume a double displacement reaction. At least ideally. 2KI + CaS -> K2S + CaI2
The balanced chemical equation for the reaction between lead (II) nitrate (Pb(NO3)2) and potassium iodide (KI) is: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3 This equation is already balanced as it has the same number of atoms of each element on both sides of the reaction arrow.
The balanced chemical equation for the reaction between chlorine gas (Cl2) and potassium iodide (KI) is: Cl2 + 2KI --> 2KCl + I2
The chemical formula for potassium iodide is KI. When dissolved in water, it dissociates into potassium ions (K+) and iodide ions (I-). The equation for this dissociation is written as: KI → K+ + I-.
The balanced equation is 2KI + Cl2 -> 2KCl + I2. This is balanced by ensuring that there are the same number of each type of atom on both sides of the equation.