CuOH + 3H2SO4 --> CuSO4 + 3H2O
equation = copper+suphuric acid=copper sulphate+hydrozen
equation = copper+suphuric acid=copper sulphate+hydrozen
Copper oxide+ Sulphuric acid ----> copper sulphate +water
Copper sulfate is a reactant in the equation as stated, because it is present before the reaction has occurred and no longer present afterward.
Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2 Copper (Cu) on reacting with two moles of sulphuric acid (H2SO4) yields copper sulphate (CuSO4) and 2 moles of water (2H2O) and sulphur dioxide (SO2).
equation = copper+suphuric acid=copper sulphate+hydrozen
equation = copper+suphuric acid=copper sulphate+hydrozen
Solution of Copper(2) sulphate is acidic in nature. This is due to the fact that in solution, copper sulphate reacts with water to produce copper(2)hydroxide and sulphuric acid: CuSO4 + H2O ------> Cu(OH)2 + H2SO4 Copper hydroxide is a weak base whereas Sulphuric acid is a very strong acid. Due to presence of a strong acid (sulphuric acid) this solution is acidic in nature. :)
Copper oxide+ Sulphuric acid ----> copper sulphate +water
SO4H2 + 2Cu --> SO2 + 2CuOH
Copper sulfate is a reactant in the equation as stated, because it is present before the reaction has occurred and no longer present afterward.
Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2 Copper (Cu) on reacting with two moles of sulphuric acid (H2SO4) yields copper sulphate (CuSO4) and 2 moles of water (2H2O) and sulphur dioxide (SO2).
The compound copper (III) chloride doesn't exist !
The salts of sulfuric acid are named sulfates.
Copper carbonate + sulphuric acid = copper sulphate + water + carbon dioxide
CuSO4 is a salt of weak base(copper hydroxide) and strong acid(sulphuric acid)....the Ph of the solution of cuso4 will be acidic....
Cu (OH)2 = CuO2 + H2O