The complete ionic equation would be2Na^2(aq) + SO4^2-(aq) + Ca^2+(aq) + 2Cl^-(aq) =>2Na^+(aq) + 2Cl^-(aq) + CaSO4(s)
SO4²-(aq)+ CaCl2(aq)----> CaSO4(s)
2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+(aq) + 2Cl-(aq)
The complete ionic equation for copper sulfate (CuSO4) plus sodium carbonate (Na2CO3) is: Cu^2+ (aq) + SO4^2- (aq) + 2Na^+ (aq) + CO3^2- (aq) → CuCO3 (s) + Na2SO4 (aq). This equation shows the dissociation of all ions in the reactants and products.
The net ionic equation for calcium chloride (CaCl2) in water is: Ca2+(aq) + 2Cl-(aq) -> CaCl2(s) This equation shows the dissociation of calcium chloride into its ions in water.
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.
Molecular equation: CuSO4 + Na2CO3 → CuCO3 + Na2SO4 Net ionic equation: Cu2+ + CO3^2- → CuCO3
The complete ionic equation for copper sulfate (CuSO4) plus sodium carbonate (Na2CO3) is: Cu^2+ (aq) + SO4^2- (aq) + 2Na^+ (aq) + CO3^2- (aq) → CuCO3 (s) + Na2SO4 (aq). This equation shows the dissociation of all ions in the reactants and products.
2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+(aq) + 2Cl-(aq)
The net ionic equation for NaOH and Na2SO4 when they form a precipitate is simple. It will contain only the atoms that participate in the reaction. Both of these compounds are soluble.
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.
the spectator ions are removed
The complete ionic equation for potassium carbonate (K2CO3) reacting with hydrochloric acid (HCl) is: 2K+(aq) + CO3^2-(aq) + 2H+(aq) + 2Cl-(aq) → 2K+(aq) + 2Cl-(aq) + H2O(l) + CO2(g)
ionic
Ionic
CaCl2 is an ionic compound forming a giant lattice.
Ca (2+) + CO3 (2-) --> CaCO3
You should have written CaCl2(aq) + 2AgNO3(aq) → Ca(NO3)2(aq) + 2AgCl(s) (The Precipitation reaction) The full ionic equation though is ............................. Ca2+ + 2Cl- + 2Ag+ + 2NO3- → Ca2+ + 2NO3- + 2AgCl(s)
No, CaCl2 is formed by an ionic bond. Calcium (Ca) is a metal and chlorine (Cl) is a non-metal, so they form an ionic bond where electrons are transferred from the calcium to the chlorine atoms.