Cl2 stands for Chlorine.I2 stands for Iodine.
I2 is deep purple color. Br2 is a reddish brown, Cl2 is a green. F2 is yellow.
O2, N2, Cl2, I2, as well as F2, Br2, and H2 are all diatomic elements.
I2
I2 + 2Cl2 .==> ICl + ICl3 molar mass of I2 = 127 molar mass of Cl2 = 70.9 moles of I2 used = 25.4/127 = 0.2 moles of I2 moles of Cl2 used = 14.2/70.9 = 0.2 moles of Cl2 Since the stoichiometry indicates that each mole of I2 reacts with 2 moles of Cl2 to give 1 mole each of ICl and ICl3, you should get 0.1 moles of each product. The reason you don't get 0.2 moles is because the amount of I2 is limiting, and you can see that 2 moles of Cl2 will use up 1 mole of I2, so 0.2 moles of Cl2 will use up 0.1 moles of I2. So 0.1 moles of product is all you can get under these conditions
Cl2 has the maximum bond energy i the above mentioned compounds.
I is replaced by Cl.So KCl and I2 is formed.
I2 is deep purple color. Br2 is a reddish brown, Cl2 is a green. F2 is yellow.
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
O2, N2, Cl2, I2, as well as F2, Br2, and H2 are all diatomic elements.
I2
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Balanced equation for Sodium and Chlorine is: 2Na + Cl2 --> 2NaCl
I2 + 2Cl2 .==> ICl + ICl3 molar mass of I2 = 127 molar mass of Cl2 = 70.9 moles of I2 used = 25.4/127 = 0.2 moles of I2 moles of Cl2 used = 14.2/70.9 = 0.2 moles of Cl2 Since the stoichiometry indicates that each mole of I2 reacts with 2 moles of Cl2 to give 1 mole each of ICl and ICl3, you should get 0.1 moles of each product. The reason you don't get 0.2 moles is because the amount of I2 is limiting, and you can see that 2 moles of Cl2 will use up 1 mole of I2, so 0.2 moles of Cl2 will use up 0.1 moles of I2. So 0.1 moles of product is all you can get under these conditions
Cl2 has the maximum bond energy i the above mentioned compounds.
I2 is an Element. It is the chemical symbol for molecular iodine.
It is not a compound, it is the element iodine.
Redox reaction.