The difference in voltage on the electro-chemical series of the 2 constituent elements.
0V
Equilibrium potential is referring to the equilibrium (or balance) established between the forces of diffusion and electrical forces specific to each ion. For example, the equilibrium potential for Potassium, K+, in a cell with a semi permeable membrane is -80mV or Ek+=80mV. The membrane potential, on the other hand, refers to the voltage across the membrane at anytime and takes into account a range of equilibrium potentials such as Potassium, Sodium etc.
A transformer must be connected to an alternating current (AC) supply of the correct voltage.
The fan motor draws extra voltage from the AC line when it starts. Once the fan is turning it does not require as much energy to keep it spinning, so the voltage equilibrium is restored.
Phase to Phase voltageCorrection to the above answer:There is no such thing as a 'phase-to-phase' or 'phase-to-ground' voltage. The correct terms are 'line-to-line' (or 'line voltage') and 'line-to-ground' (or 'phase voltage'). Transmission-line voltages are line-to-line (or 'line') voltages.
To answer this question the voltage of the shower is needed.
Capacitors resist a change in voltage, proportional to current and inversely proportional to capacitance. In a DC circuit, the voltage is not changing. Therefore, after equilibrium is reached, there is no current flowing through the capacitor.
Zero.
After breakdown voltage is reached in a zener diode the current increases drastically.
The barrier voltage of a diode is 0.7v for silicon and 0.3 for germanium. after this voltage is reached the current starts increasing rapidly... till this voltage is reached the current increases in very small steps...
A capacitor will appear to be an open circuit to a DC source, but only after equilibrium is reached. Proof: A capacitor resists a change in voltage. The equation is ... dv/dt = i/c ... which means that the rate of change of voltage in volts per second is equal to current in amperes divided by capacitance in farads. A DC source has constant voltage. If you charge a capacitor to a constant voltage, then, at equilibrium, dv/dt is zero. This means that i must also be zero, since c is not zero. Ohm's law states that resistance is voltage divided by current. The limit of this is that, when current is zero, then resistance must be infinity. Therefore, the capacitor will have infinite resistance and appear to be open circuited.
A: TRIAC will break over and conduct at a certain if a certain voltage is reached. That voltage depends on all different triacs devices
if you have checked the voltage with a dvom then you need to verify that the power source at the fuel pump relay is correct, if it has the correct voltage pre-relay then your problem is post-relay. if the voltage is not correct pre-relay then simply trace and repair the power source. if the problem is post relay then check the output voltage directly at the relay, if voltage is good trace and repair line from relay to pump. if voltage is not correct then replace the fuel pump relay
Yes it does. You just choose the correct size tip and voltage to match your Asus
maximum or peak value
A: THAT IS CORRECT a diode conducts only one way that is why it is called a semiconductor Reversing the voltage no current will flow until breakdown.
It is the CE (collector - emitter) voltage at a given collector current when the transistor is fully on. Increasing the base current will not lower the CE voltage any more once saturation has been reached.
Yes. The correct voltage is detected based on keying or signaling from the processor.