the basic operation of 3watt 8ohm speaker
Amplifier power and impedance are not related, although a lower impedance speaker will be louder. Most home stereos cannot drive loads below 4 ohms, however, so using this 3 ohm speaker with a home theater may cause the amp to go into protection mode or shut down completely. Check your owner's manual to see what impedance of speaker your receiver can safely drive.
If you connect four four-ohm speakers in parallel, the impedance will be equal to 1 ohm, and will allow the speakers to run at the advertised watt RMS. The equation is 1/(total impedance) = 1/(impedance 1) + 1/(impedance 2) and so on. Parallel is like this: Power source: + Speaker+: + + + + Speaker-: - - - - Power source: - However, usually if you hook up a 4 ohm speaker to a 1 ohm amplifier, it would still function it would simply not provide nearly as much wattage as it would have otherwise. Also, if your speakers are dual voice coil (like many subwoofers) you could use 2 4 ohm speakers, connecting the two voice coils on each speaker in parallel and then connecting the speakers themselves in parallel.
The answer is volt.
If you mean as pairs, yes. put an 8 Ohm and a 16 Ohm speaker in parallel for each channel. The 16 Ohm speakers will take 1/3 the power and the 8 Ohm speakers will take 2/3 the power. The resulting impedance will be 5.33 Ohms.
Yes, you can safely use a 4 ohm amp with one 8 ohm speaker, but you will not achieve full power. The 4 ohm amp is designed to supply a certain voltage into a 4 ohm speaker. Supplying that same voltage to an 8 ohm speaker will result in half the power, or -3dB. For maximum power, use a 4 ohm speaker, or two 8 ohm speakers in parallel.
In case of parallel combination watt increases with respect to series combination. Let, V=12v,Ra=5 Ohm, Rb=3 Ohm then Rse=Ra+Rb=8 Ohm Rpa=Ra.Rb/(Ra+Rb)=1.875 Ohm Now, P=IV or V^2/R then Pse=12^2/8=18W Ppa=12^2/1.875=76.8W So from here we can easily understand that why watt increases in parallel combination w.r.t series combination.
First thing you need to do is calculate the Voltage across the 8 ohm resistor. As it is in parallel with the 1 & 3 ohm resistors in series that would be the voltage across those two. P = E^2 / R thus P x R = E^2; 2 watt x 8 ohms = E^2 = 4V Quick check: I = E / R = 4 / 8 = 0.5 A P = E x I = 4 x 0.5 = 2 watts Now Rt = 1 ohm + 3 ohms = 4 ohms Caclulate current in the series circuit: I = E / R = 4V / 4 ohms = 1A Now calaculate the power in the 3 ohm resistor: P = I^2 x R = 1 x 3 = 3 Watts. (NOTE: I am using the ^2 to show exponents, in this case it means squared)
The 2- 4 ohm speakers can be hooked up in series to make 8 ohms. you cant hook up the 2- 6 ohm, cause if you put them in series, you have 12 ohms. If you put them in , parallel you have 3 ohms out from av to +(4ohms), -(4ohms) to +(4ohms), -(4ohms) to - av. And do the math 4ohms plus 4ohms equals 8ohms. doing the math on the 2- 6ohm speakers... 6ohms + 6 ohms = 12ohms I dont think 12ohms would blow your system, but it wont sound right. now if you raise the volume too loud on the av you will blow the speaker coils out you may boost the wattage of the 2-4ohm speakers (in series) to maybe 70 watts total ******************************************* If you connect loudspeakers in series, the amplifier can not properly damp them, but, unless you are a fairly critical listener, you perhaps won't detect the difference. Connecting two 6 ohm 'speakers in series will give a load of 12 ohms, and will not "blow" anything. Connecting a load impedance higher than the amplifier's design load will do no harm at all. The only disadvantage is that the amplifier will not be able to develop its rated power output.
4, 1 3 ohm resistor in series with 3 3 ohm resistors in parallel.
2 in series with 3&4 in parallel
5CommentThe plural of ohm is ohms, not ohm's!
There is really no 4 ohm or 8 ohm amplifier on the market with an output impedance of 4 or 8 ohms for power matching. You will find there 0.4 ohm or less for voltage bridging. There is really no 4 ohm or 8 ohm amplifier on the market with an output impedance of 4 or 8 ohms for power matching. You will find there 0.4 ohm or less for voltage bridging.