A zero-watt bulb is a lightbulb that uses little power. Contrary to the name, these bulbs are not in fact zero watts. The reason they are colloquially called "zero watt" bulbs is because when they were first made, they only had a power consumption rate of 15W but testing equipment at the time was unable to detect such low wattage causing people to think they didn't use any power.
Todays "zero watt" bulbs are as little as 10W.
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Hardly "zero watt" then. I wonder if the term was originally an advertising slogan as misleading as "zero carbon homes", because I cannot believe it was impossible to measure a power below 15W at the time these lamps were invented, even if indirectly from the Voltage and Current. (W = V x I ).
The question does not make sense. No one would build a zero watt bulb, because that would dissipate no power and do no work. It would be senseless. Perhaps the question was mis-stated. Please restate the question.
If it takes 0 watts it is probably drawing 0 current. However a capacitor can draw near to 0 watts while current flows, because power is taken from the supply and returned twice during each AC cycle.
A 0 watt bulb takes rather more than 0 watts, maybe 5 or 10 watts at the supply voltage of the property where it's used.
A zero watt bulb is considered a bulb who's filament has broken. With an open circuit no current will flow. With no flow of current there will be no circuit power. So the answer will be zero consumption for a bulb with no filament.
A "zero watt" bulb consumes no power. However, it also will produce no light output.
Well, you could turn it off...
Any light bulb which is emitting light is consuming power of some kind. There's no such thing as a "zero watt bulb".
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Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
Multiply the current by the voltage: 120 times 0.3, which is 40 watts.
The bulb is marked with the power (watts) and the voltage. Divide the watts by the volts and you have the amps.
Depends on the wattage of the bulb. Formula is Power (watts) = Voltage * Current (A). Therefore for a 55w bulb, in a 12V car, bulb draws 4.6Amps.
Lamps use whatever voltage they are designed to run on. If the question as asking about the energy used, this is measured in watts. Watts are calculated as: W (watts) = V (volts) x I (amps) which is the product of the voltage and the current drawn.
Power is current times voltage, so a current of 0.5 amperes and a voltage of 220v across a bulb will yield a power of 110 watts.
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.
Look on the light bulb for the voltage and the power in watts. Then divide the watts by the voltage and that gives the amps. Some CFL bulbs also state the current as well as the voltage and power, which is because they can have a poor power factor.
Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
Multiply the current by the voltage: 120 times 0.3, which is 40 watts.
The bulb is marked with the power (watts) and the voltage. Divide the watts by the volts and you have the amps.
Depends on the wattage of the bulb. Formula is Power (watts) = Voltage * Current (A). Therefore for a 55w bulb, in a 12V car, bulb draws 4.6Amps.
Lamps use whatever voltage they are designed to run on. If the question as asking about the energy used, this is measured in watts. Watts are calculated as: W (watts) = V (volts) x I (amps) which is the product of the voltage and the current drawn.
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Find out your supply voltage, and divide 65 by it: I(amps) = P(watts)/V(volts) = 65/V
If you divide the watts of the bulb by the supply voltage, that is the current. For example a 60 w bulb on a 240 v supply gives a current of 60/240 which is ¼ amp.
Think about an electric light bulb connected to power through a dimmer. As you reduce the voltage the bulb gets dimmer and provides less wattage and less light. That is less work is being done. Hence power is reduced.Where did the voltage go?If the bulb is 60W, R=1202/60=240 ohmsand you add say a 100 ohm maximum resistive dimmer,your total resistance for the circuit is now 340 ohmsyour current is 120 V / 340 ohms = .3529 ampsvoltage drop across the dimmer is .3529 amps x 100 ohms = 35.29 volts120 - 35.29 = 84.71 volts left for the light84.71 V x .3529 amps = 29.89 watts consumed by the light29.89 watts is < 60 watts more than 50% savings!?35.29 V x .3529 amps = 12.454 watts consumed by the dimmer29.89 W + 12.454 W = 42.344 watts total consumed in this circuit42.344 watts is still less than 60 watts by 17.656 watts, butYou have less than 50% light output and still consume more than 70% of the original power! Not very efficient.AnswerFirst of all, appliances do not consume power; they consume energy. Power merely indicates the rate at which energy is consumed. Secondly, assuming the appliance's resistance remains constant (not necessarily the case) power is proportional to the square of the voltage. So, reducing the voltage will significanly reduce the power of the appliance.