12 amps
14 ohm X 20 A = 240 V (V=IR) the answer is 280 14x20 is 280!
Assuming a pure resistive load Ohm's Law tells us 240 / 8 = Current = 30 Amps. Watts = Volts x Amps so 240 x 30 = 7,200 Watts = 7.2 KW.
current = voltage/resistanceAssuming the 240 volts is across the 100 ohm wire, 2.4 amperespower = current * voltageResulting in the wire dissipating 576 watts... One hot wire!
The unit of Current is Ampere. Abbreviation of Current is 'I' and that of Ampere is 'A'. The unit of Resistance is ohm. Abbreviation of Resistance is 'R' and that of ohm is the symbol of 'omega' or the symbol of 'ohm'.
Ohm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.Ohm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.Ohm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.Ohm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.
VOLTS x (VOLTS/OHMS) = WATTS 240 X (240/8) = 7200 Watts = 7.2KWatts
2 amps
4.12A. V=IR
14 ohm X 20 A = 240 V (V=IR) the answer is 280 14x20 is 280!
41.6
Assuming a pure resistive load Ohm's Law tells us 240 / 8 = Current = 30 Amps. Watts = Volts x Amps so 240 x 30 = 7,200 Watts = 7.2 KW.
240 heater on 120 volts The load is a resistive load and as such it is governed by Ohm's law. Current is directly proportional to the voltage and inversely proportional to the resistance. As the voltage goes down so does the current. For example take a 2200 watt heater at 220 volts = 10 amps. R = E/I = 220/10 = 22 ohms of resistance in the heater. Now take the 2200 watt heater and using the same formula and at 110 volts. I = E/R, Amps = Volts / Resistance. 110/22 = 5 amps. As you can see ohm's law holds true, the current is inversely proportional to the resistance and as the voltage goes down so does the current. To answer the question, yes a 220 volt heater will run on a 110 volt circuit but at 1/4 of the wattage that the heater is rated at. W = A x V = 5 x 110 = 550 watts.
The resistance of a lamp operating at 115 volts and using 0.25 amp of current is 460. The relationship I used is Ohm's law.
current = voltage/resistanceAssuming the 240 volts is across the 100 ohm wire, 2.4 amperespower = current * voltageResulting in the wire dissipating 576 watts... One hot wire!
ohm's law state that in an electric current it is propotional to current
50 ohms...!
50