you should specify:
- circuit topology, I assume a series connection.
- diode allows current flow? It depends how it's connected
- diode forward voltage drop value
if diode is in forward conduction, you have VR=10V - VDIODE and, thus, I = VR/R=(10-Vdiode)/1200.
In a reverse bias condition of a circuit current initially remains the same for low voltage but at the breakdown voltage current increases fast even for a small increase in voltage.hence.........
The diode voltage drop is 0.7 volts, so you need that much to turn it on. Current is controlled by a resistor in series.
Allows 1 way current/voltage flow
A zener diode, in the reverse bias condition, presents a higher voltage. The current, however, is a function of the supplying circuit.
Consider ideal diode to be connected in series with resistor of 6kSilicon diode forward bias voltage = 0.7 voltsCurrent across 6k resistor = (5-0.7)/6000 amperesVoltage across {resistor + diode}=4.3 + 0.7=5vIf silicon internal resistance is 6k then voltage across diode=5vIf external resistance is 6k and diode resistance is negligible then voltage across diode=0.7v
Forward biase the given diode by using a Variable resistor in the circuit. By adjusting the value of variable resistor you will adjust the voltage being applied to junction diode. First adjust the resistance such that no(negligble) current flows through the circuit. Now start decreasing the value of resistance. Note the voltage across resistor(Vr) when current just starts flowing through the circuit. Then Potential barrier of diode will be: Vb=V-Vr Vb:Barrier Potential V:Battery Voltage Vr:Voltage Drop across resistance when current just starts flowing through the circuit.
In a reverse bias condition of a circuit current initially remains the same for low voltage but at the breakdown voltage current increases fast even for a small increase in voltage.hence.........
None. A diode does not have a resistor in it. Diodes and resistors are different devices used for different purposes. For example, increasing current flow through a resistor increases the voltage drop across the resistor. Increasing current flow through a diode (within the diode's capabilities, just the same as a resistor) will actually decrease the voltage drop across the diode (once the diode "turns on" this voltage variance will be fairly small, though).
No. A zener diode is a voltage limiter. Circuit design might create a current limiting response, but the basic control is voltage, not current.
For answering this question we have to consider the constant voltage drop model of the diode which says that if voltage across diode is less then its cut in voltage than assume diode to be open circuit and if it is greater then assume diode to be short circuit.Till the input voltage is less than the cut in voltage, diode is open circuit(thus no current through the circuit). Thus entire input voltage appears across the diode as output.When input voltage is greater than or equal to cut in voltage, then short circuit the diode. Thus, there will be no voltage drop across the diode as output.Thus cut in voltage decides when to consider the diode open circuit and when short circuit. It decides when the diode will have output when it will not.
The resistor limits current so you can measure voltage across the diode. When you forward bias and saturate a junction, the voltage across it will be constant (0.7 in silicon, for example).
The diode voltage drop is 0.7 volts, so you need that much to turn it on. Current is controlled by a resistor in series.
The zener diode is neither a voltage amplifier nor a current limiting device but can be used in oscillator circuits to supply a constant output voltage.
Allows 1 way current/voltage flow
A zener diode, in the reverse bias condition, presents a higher voltage. The current, however, is a function of the supplying circuit.
Consider ideal diode to be connected in series with resistor of 6kSilicon diode forward bias voltage = 0.7 voltsCurrent across 6k resistor = (5-0.7)/6000 amperesVoltage across {resistor + diode}=4.3 + 0.7=5vIf silicon internal resistance is 6k then voltage across diode=5vIf external resistance is 6k and diode resistance is negligible then voltage across diode=0.7v
you could use a current limiting diode such as a Zenner, or a current limiting resistor in series with the LED