In a reverse bias condition of a circuit current initially remains the same for low voltage but at the breakdown voltage current increases fast even for a small increase in voltage.hence.........
you should specify: - circuit topology, I assume a series connection. - diode allows current flow? It depends how it's connected - diode forward voltage drop value if diode is in forward conduction, you have VR=10V - VDIODE and, thus, I = VR/R=(10-Vdiode)/1200.
When a diode passes from forward biased to reverse biased it takes a short period of time for the charge carriers in the vicinity of the junction to recombine and create a nonconducting depletion region. During this time period the diode conducts in the reverse direction, this is called the reverse recovery time. Its different for every kind of diode, to get the value for a specific diode consult the datasheet.
It resist the flow of current according to the resistance value.
A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.
Normally if a resistor fails they will either increase in value or open up at all (open circuit).
A specified amount of current is allowed to flow through the diode. if the current passing through the diode exceeds the specific value, the diode gets heated and is likely to be damaged. therefore in a biasing circuit a resistance R has been applied , which limits the current passing through the diode within a specific value.
the current which has negative value n passes through the diode is called as diode reverse current
Forward biase the given diode by using a Variable resistor in the circuit. By adjusting the value of variable resistor you will adjust the voltage being applied to junction diode. First adjust the resistance such that no(negligble) current flows through the circuit. Now start decreasing the value of resistance. Note the voltage across resistor(Vr) when current just starts flowing through the circuit. Then Potential barrier of diode will be: Vb=V-Vr Vb:Barrier Potential V:Battery Voltage Vr:Voltage Drop across resistance when current just starts flowing through the circuit.
you should specify: - circuit topology, I assume a series connection. - diode allows current flow? It depends how it's connected - diode forward voltage drop value if diode is in forward conduction, you have VR=10V - VDIODE and, thus, I = VR/R=(10-Vdiode)/1200.
if not disconnected you will measure the resistance of the circuit in parallel with the resistor.
to determine the comparison of resistance value of both forward and reverse diode . The more the resistance the lower the current , the lower the resistance the higher the current . When reverse bias , the resistance is high and it acts in open circuit and the reverse current is very small that can be neglected . When forward bias , the resistance is low and it acts as short circuit and the forward current is increasing as the voltage supply is higher .
50V or larger
when a resistor is connected in a circuit it drop some voltage across it.when a circuit have large input voltage then by using a resistor of suitable value we get the desired voltage.
When a diode passes from forward biased to reverse biased it takes a short period of time for the charge carriers in the vicinity of the junction to recombine and create a nonconducting depletion region. During this time period the diode conducts in the reverse direction, this is called the reverse recovery time. Its different for every kind of diode, to get the value for a specific diode consult the datasheet.
Short answer: By using a varactor diode as the capacitance in a parallel resonant ckt, by changing the reverse bias voltage you change the value of capacitance which in turn changes the resonant frequency. This makes a tuneable resonant ckt.
its about 1000 v
In the circuit it is connected to other devices with their own properties that can influence your reading. Out of circuit you just measure the resistor. It has the same value both ways.