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What is the density of a shampoo if 13.2G of shampoo fills a 5-ml container?
Wiki User
∙ 9y ago
2.64 g/mL
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∙ 9y ago
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How many grams does 3 moles of CO2 weigh?
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
What is the mass of 1 mol of C6H12O6?
C6H12O6 is the molecular formula for sugar (glucose).Molecular mass/ molecular weight = (Number of C atoms) (Atomic weight of C) +(Number of H atoms) (Atomic weight of H) +(Number of O atoms) (Atomic weight of O) = (6) (12) + 12 (1) + 6 (16) = 180 (g/mole)
What is the total volume occupied by 132g of CO2 at STP?
For this problem you have to use PV=nRT. In order to get anywhere with the question, you have to isolate the V (volume) and get it alone. To do that, you have to divide each side by P (pressure). When you do that, your new formula to work with is: V = nRT / P (the P cancelled out on the other side, which left you with V) Unfortunately, you weren't given the number of moles in the problem. Instead, they made it a bit more challenging by giving you the number of grams, which can be converted to give you your number of moles: 42 g / 1 ( 1 mole / 28.01 g) = 1.5 moles of CO Now, you have all the information that you need in order to answer the question. All you have to do now is plug in, but make sure that you know where everything goes: n (moles) = 1.5 moles R = .0821 L atm / mole K <-----that one looks weird, but that's all required for R T (temp) = 273 K <----that's your standard temp *must be in Kelvin!!!! ALWAYS!! P (pressure) = 1 atm <----standard pressure for P *must be in atm!! ALWAYS!! Your equation should now look like this: V= (1.5 moles x .0821 Latm/ moleK x 273 K) / (1 atm) = 34 L CO And then you get your answer!
What is the number of moles in 132g Ba NO3 2?
Ba(NO3)2The total mass for this molecule is 261gso what is 261g/132g this is 1.97moles
How long does it take a 100.00g sample of As-81 to decay to 6.25g?
132g
How do you get 132g of tomato in 100g of ketchup?
Tamatoes lose weight as they are cooked.
How many grams does 3 moles of CO2 weigh?
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
What is the mass of 1 mol of C6H12O6?
C6H12O6 is the molecular formula for sugar (glucose).Molecular mass/ molecular weight = (Number of C atoms) (Atomic weight of C) +(Number of H atoms) (Atomic weight of H) +(Number of O atoms) (Atomic weight of O) = (6) (12) + 12 (1) + 6 (16) = 180 (g/mole)
What is the total volume occupied by 132g of CO2 at STP?
For this problem you have to use PV=nRT. In order to get anywhere with the question, you have to isolate the V (volume) and get it alone. To do that, you have to divide each side by P (pressure). When you do that, your new formula to work with is: V = nRT / P (the P cancelled out on the other side, which left you with V) Unfortunately, you weren't given the number of moles in the problem. Instead, they made it a bit more challenging by giving you the number of grams, which can be converted to give you your number of moles: 42 g / 1 ( 1 mole / 28.01 g) = 1.5 moles of CO Now, you have all the information that you need in order to answer the question. All you have to do now is plug in, but make sure that you know where everything goes: n (moles) = 1.5 moles R = .0821 L atm / mole K <-----that one looks weird, but that's all required for R T (temp) = 273 K <----that's your standard temp *must be in Kelvin!!!! ALWAYS!! P (pressure) = 1 atm <----standard pressure for P *must be in atm!! ALWAYS!! Your equation should now look like this: V= (1.5 moles x .0821 Latm/ moleK x 273 K) / (1 atm) = 34 L CO And then you get your answer!
