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For this problem you have to use PV=nRT.

In order to get anywhere with the question, you have to isolate the V (volume) and get it alone. To do that, you have to divide each side by P (pressure). When you do that, your new formula to work with is:

V = nRT / P

(the P cancelled out on the other side, which left you with V)

Unfortunately, you weren't given the number of moles in the problem. Instead, they made it a bit more challenging by giving you the number of grams, which can be converted to give you your number of moles:

42 g / 1 ( 1 mole / 28.01 g) = 1.5 moles of CO

Now, you have all the information that you need in order to answer the question. All you have to do now is plug in, but make sure that you know where everything goes:

n (moles) = 1.5 moles

R = .0821 L atm / mole K <-----that one looks weird, but that's all required for R

T (temp) = 273 K <----that's your standard temp *must be in Kelvin!!!! ALWAYS!!

P (pressure) = 1 atm <----standard pressure for P *must be in atm!! ALWAYS!!

Your equation should now look like this:

V= (1.5 moles x .0821 Latm/ moleK x 273 K) / (1 atm) =

34 L CO

And then you get your answer!

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12y ago
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9y ago

Vstp = ( n ) ( 22.42 L/mol ) = ( m/M ) ( 22.42 L/mol )

Vstp = ( 92.31 g / 44.01 g per mol ) ( 22.42 L per mol at STP )

Vstp = ( 2.097 mol ) ( 22.42 L/mol )

Vstp = 47.03 L <-----[ Answer ]

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8y ago

The volume is 46,69 L.

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8y ago

The volume is 66,77 mL.

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11y ago

2.24 L

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11y ago

8.96 cm3

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Q: What is the total volume occupied by 132g of CO2 at STP?
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