NaOH(s) is solid and mostly pure sodium hydroxide. NaOH(aq) is sodium hydroxide dissolved in water.
Na+H2O → NaOH+H2 Then you balance it to get: 2Na + 2H2O → 2NaOH + H2
Zn (s) + 2HCI (aq) -- H2 (g) + ZnCI2 (s) Apex
There's two possible reactions Zink with solid NaOH gives double salt Zn + 2NaOH --t--> Na2ZnO2 + H2 And I Think you need the other one: Zink with NaOH(aq) gives the complex salt: Zn + 2NaOH + 2H2O --> Na2[Zn(OH)4] + H2
Lithium atom become the cation Li+.
H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
AgNO3(aq) + NaOH (aq) à AgOH(s) + NaNO3(aq)
HCl (aq) + NaOH (s) → NaCl (aq) + H2O (l)
BeCl2(aq) + 2NaOH(aq) -> 2NaCl(aq) + Be(OH)2(s) Be(aq) + 2OH(aq) -> Be(OH)2(s) Hope this helps!
CuSO4(aq) + 2 NaOH(aq) --> Cu(OH)2(s) + Na2SO4(aq)
The dissociation reaction for sodium hydroxide in water is as follows: NaOH(s) ---> Na+(aq) + OH-(aq)
It goes from 0 to +1
Zn(s) + 2 OH-(aq) -> ZnO22-(aq) + H2 (g) Perhaps a bit more may be needed Zn(s) + H2O(l) +2OH-(aq) -> Zn(OH)42-(aq) + H2(g)
Na+H2O → NaOH+H2 Then you balance it to get: 2Na + 2H2O → 2NaOH + H2
Zn (s) + 2HCI (aq) -- H2 (g) + ZnCI2 (s) Apex
Na2CO3 + 2 NH4OH = (NH4)2CO3 + 2 NaOH
NaCl(s) + C2H5OH(l) --> NaOH(aq) + C2H5Cl(aq)
Ni2+(aq) + SO42-(aq) + 2 Na+(aq) + 2 OH-(aq) ==> Ni(OH)2(s) + 2 Na+(aq) + SO42-(aq), the ionic equation is ; Ni2+(aq) + 2 OH-(aq)==> Ni(OH)2(s)