The number preceding the name of a sublevel ("s") indicates in which electron shell it belongs. Thusly, 2s is the second shell and 3s is the third.
1s 2s 3s 3p 4s 3d 4p
1s 2s 2p 3s 3p 4s 3d 2p
1s, 2s, 2p,3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d
P is Phosphorus 1s2 2s2 2p6 3s2 3p3 or [Ne] 3s2 3p3
Any atom with unpaired electrons in it's orbital exhibits paramagnetism, that is that it will be attracted into an inducing magnetic field. Phosphorous has 15 electrons: 1s>2e-(all paired) 2s>2e- 2p>6e-(all paired) 3s>2e-(these two are paired) 3p>3e-(note that these are the unpaired electrons that cause it to be paramagnetic) All this is because a moving negative charge produces a magnetic field if there are two electrons in the same orbital they always spin in opposite directions cancelling each other out. When there are unpaired electrons that creates the magnetic field.
The 2s orbital and 3s orbital both have the same spherical shape and can hold a maximum of two electrons of opposite spin. They only differ because the 3s orbital is further out from the nucleus than the 2s orbital, thus the 3s orbital has a higher energy value.
An electron in a 2s orbital is on average closer to the nucleus.
Two per level (that is, 2 1s, 2 2s, 2 3s, etc.)
There are 9 occupied orbitals in a phosphorus atom's ground state: one 1s orbital, one 2s orbital, three 2p orbitals, one 3s orbital, and three 3p orbitals.
NO
The electrons in the 2p subshell have more energy than those in the 2s subshell, that is energy per electron.See Wikipedia 'Electron Shells' for more on this subject.
All of 11 electrons in sodium are in different electron orbitals: 2 electrons are in 1s orbital, 2 in 2s, 6 in 2p and 1 in the 3s orbital. (This last one is the so-called valence electron)
The are two electrons in the 3s orbital of magnesium (Mg.)
7-2s+4+5s ..... Okay first you combine like terms(add the like terms)..so its going to be 11+3s I did 7+4=11 then -2s+5s=3s So the answer can be 11+3s or 3s+11
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
Yes, it exists. If you write the orbitals in order of increasing energy, then you get it. The order is:- 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p..................... Here, you get the 3s orbital at the 4th place.
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0