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What is the distance from the Earth's center to a point outside the Earth where the gravitational acceleration due to the Earth is 145 of its value at the Earth's surface?
Wiki User
∙ 11y ago
We know its value at a distances of 6378 km from the centre, that is where most of us are. It is an inverse-square force, so to experience 1/145th of the force you have to go to sqrt(145) times further away, which is a distance of 76,800 km.
The force acting on the Moon is 1/3500 of what it is on the Earth's surface, which is why the Moon accelerates towards us at 2.8 mm/sec^2. But that is combined with a sideways velocity of 1 km/sec so it never hits us, it just keeps on going round in circles.
Wiki User
∙ 11y ago
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Is the pull of a black hole measured in g's?
Normally not, since there is no surface on which you might stand, where you would feel its gravity. Of course, you can calculate the gravitational acceleration at any point, but the distance to the black hole would have to be specified.
How much more is the gravitational force of the earth than the moon?
The acceleration of gravity on the moon is about 1/6th the acceleration of gravity on earth. Any mass on the earth's surface feels about 6 times the downward force that it would feel on the surface of the moon.
What is value of gravitational acceleration?
At the Earth's surface the nominal value is about 9.8 m/s2. The exact value varies from place to place.
What height beyond the earth surface the gravitational force of earth is inactive?
There is no distance from Earth where the force of gravitational attraction toward it is 'inactive'.The formula for the forces of gravity gives the magnitude of the force at any distance.Note: Any distance.
What is the relation between surface tension and acceleration?
i think that acceleration is directly proportional to surface tension.....
What is the planet earth's gravitational force?
This can be measured by the acceleration due to gravity at the surface. Earth's surface gravitational acceleration is about 9.8 m/s2
Why is the acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on earths surface?
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
What is the gravitational acceleration of an object on the surface of the earth?
At or near the surface of the earth, the acceleration due to gravity is 32 feet per second per second
What is the distance from the Earths center to a point outside the Earth where the gravitational acceleration due to the Earth is 1 26 of its value at the Earths surface?
That would have to be at a radius that is sqrt(26) = 5.1 times the Earth's physical radius, or about 32,486 kilometers (20,186 miles) from the center.
How do you find the weight of an object on earth?
You could weigh it against other objects. If it is not on the surface, multiply its mass by the acceleration of gravity (at that distance) to find its gravitational potential in newtons.
Why does a man get hurt when he jumps from a significant height even though newtons universal gravitational law says that height is inversely proportional to acceleration due to gravity?
The difference in gravitational acceleration depends on the distance from the centre of the earth , not the surface. The equation for the new rate of accelration calculated from the surface rate is: > a = k / ( ( d / r )2 ) > where: a = acceleration due to gravity at new position k = surface rate of acceleration ( use 9.82 (m/s)/s ) d = distance from earths centre to new position ( r + height of jump) ( 6376000 metres) r = surface radius ( use 6371000 metres ) > Even if you jump from 5,000 metres the rate of acceleration would be : > 9.8046 (m/s)/s , which is 99.84 % of the rate at the surface
Where do you experience more gravity on earths surface or earths center?
on the surfaceNote:Since the earth's composition is not homogeneous, the gravitational acceleration onthe surface is probably less than what it is some small distance below the surface,but it's certainly greater than at the center.
What is the force of gravity on a person or object on the surface of a planet?
The force of gravity on a person or object at the surface of a planet is calculated by the product of the mass of the person or object and the gravitational constant acceleration for the planet. For Earth, the gravitational acceleration is 9.8 m / s^2.
How do you overcome the factor of gravitational acceleration?
By increasing the surface area so that air resistance increases
What is the earth's gravitational constant?
At the Earth's surface, the acceleration due to gravity is 9.8 m/s2.
How does surface tension depend on surface area?
I think its depends on the nature of the liquid, the surrounding environment like (Gravitational acceleration ) and temperature
What is the field strength at a distance one Earth radius beyond the surface?
I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.
