It can supply up to 1.5 kW into a load with a perfect power factor like a convector heater, or less if the power factor is less than 1. For example a motor might have a power factor of 0.75, then only 1125 watts could be used, in other words about 1.5 horse-power.
KVA=KW*Power factor, considering PF 0.9, 6KVA=KW*0.9 KW=6/.9=6.67
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1.035 KVA
type of inverter
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
Inverter efficiency varies with DC input voltage, ambient temperature, and operating power level of the inverter. It can mean power-out divided by power-in.
KVA=KW*Power factor, considering PF 0.9, 6KVA=KW*0.9 KW=6/.9=6.67
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There are many advantages of inverter generators. Some of these advantages include having a smaller size whilst also having higher fuel efficiency and high power output.
((135AH*12V)/600VA)*85%Efficiency=2.20Hrs
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50 kva ups battery back up
Probably about 180 watts, assuming 90% efficiency.
About 180 watts assuming a 90% conversion efficiency.
One horsepower electric is 746 watts, so 30 horsepower is 22.4 KW. You don't specify the power factor or motor efficiency, so I am going to assume a power factor of 0.92 and an efficiency of 0.97, fair values for a 30 horsepower motor. Divide 22.4 KW by 0.92 and then by 0.97 and you get 25.1 KVA. Divide that by three and you get 8.4 KVA per winding. You don't say if the motor is delta or wye connected, so I'm going to assume delta, and multiply by the square root of 3 (1.732) to get 14.5 KVA per phase.
A 1-ton AC can melt a ton of ice in 24 hours. The power needed is theoretically 3517 Watts so allowing for power factor and efficiency you would need a 7 kVA generator.
In a diesel engine connected to a generator with a 23% engine efficiency, 1 liter of diesel should produce nearly 2.7 kilovolt-amperes. More with improved engine efficiency.