Something with a Cos sign
increased
Weight is a force, so you use the equation F=Ma Fw=15(9.81) Fw=147.15 Fw=150 N
The Earth's gravity will force a round object to roll down an incline (slope).
Gravity adds a force (kgs) going downhill = sin (incline angle) * mass vehicle (kgs) and detracts the force when going uphill (same equation)
gravity
( Assuming mass of object on incline plane is in kilograms (kg) ) . Force pulling down incline on object (kilogram force) = object mass * sin (incline angle) . Force of object acting on and normal to incline (kilogram force) = object mass * cos (incline angle) . Mechanical Advantage = 1 / ( sin ( incline angle ) )
increased
Weight is a force, so you use the equation F=Ma Fw=15(9.81) Fw=147.15 Fw=150 N
The Earth's gravity will force a round object to roll down an incline (slope).
Gravity adds a force (kgs) going downhill = sin (incline angle) * mass vehicle (kgs) and detracts the force when going uphill (same equation)
gravity
I don't know. Tell me for sake Fv= mg is the force needed to counter the force of gravity vertically. Fs = mg sin(a) is the force needed to counter the force of gravity up an incline.
Because the force of gravity is no longer straight down on the object, it is at an angle. thus when you have a ramp some of the force due to gravity is dispersed in the x plane, causing the force down on the y plane (vertical) due to gravity ( mass x gravity) to be less thus decreasing the amount of force needed to lift.
Moving up an incline requires extra energy to counter the force of gravity.
by increasing distance over which the force is applied
If you mean using a longer incline to reach the same height, the answer is no. Energy is the ability to do work. Work = Force x distsance. A longer incline will require less force, but since the distance is greater the total energy stays the same.
I assume you are asking this in regards to an inclined plane so I will answer it accordingly, Well Recall the equation Force = Mass x Acceleration. In the case of free falling objects Acceleration is equal to gravity, however, on an inclined plan the presence of an incline prevents the object from falling straight down. Instead it must accelerate with some component of gravity. Now recall that perpendicular forces of action on an Incline plane are calculated by Sin theta and that perpendicular forces ( the normal force) is calculated by Cos theta Hence because the object is accelerating down an incline the formula for its total force parallel to the object would be Force = mg sin theta Now if you remember, if you simply remove the mass from the above equation you will be left with the acceleration component of the problem ala the force = mass x acceleration formula. So gsintheta represents A ( acceleration) in the Force = mass times acceleration formula.