the equation for sodium nitrate and copper III iodide can be given below.Cu I 2 +2 Na No3 ->I (NO3)2 + 2NaI.
this is the balance reaction for the above.
The equation for the reaction between silver nitrate and sodium iodide is AgNO3 + NaI -> AgBr + NaNO3. The gram formula masses are 169.87 for silver nitrate, 149.89 for sodium iodide, and 84.99 for sodium nitrate. Therefore, 1.7 g of silver nitrate constitutes 1.7/169.87 or 0.010 formula mass of silver nitrate and 1.5 g of sodium iodide constitutes 1.5/149.89 or 0.010 mole of sodium iodide, to the justified number of significant digits. The reaction equation shows that the number of formula unit masses of each reactant and product are the same, so that there will be 0.85 g of sodium nitrate produced, to the justified number of significant digits.
Lead(II) iodide and Sodium nitrate
The net ionic equation is Ag+(aq) + I- --> AgI(s) The sodium (Na+) and nitrate (NO3-) are spectators as always.
A precipitate of yellow Lead iodide and Sodium nitrate are formed
Na2S + Cu(NO3)2 -> 2NaNO3 + CuS
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
in aqueous medium ppts. of copper iodide are formed which are converted into cuprous iodide and free iodine in a short time. 2NaI + Cu(NO3)2 = CuI2 + 2NaNO3 2CuI2 = Cu2I2 + I2
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The equation for the reaction between silver nitrate and sodium iodide is AgNO3 + NaI -> AgBr + NaNO3. The gram formula masses are 169.87 for silver nitrate, 149.89 for sodium iodide, and 84.99 for sodium nitrate. Therefore, 1.7 g of silver nitrate constitutes 1.7/169.87 or 0.010 formula mass of silver nitrate and 1.5 g of sodium iodide constitutes 1.5/149.89 or 0.010 mole of sodium iodide, to the justified number of significant digits. The reaction equation shows that the number of formula unit masses of each reactant and product are the same, so that there will be 0.85 g of sodium nitrate produced, to the justified number of significant digits.
Produces Silver iodide precipitate and Sodium nitrate
Lead(II) iodide and Sodium nitrate
Equation: NaI + AgNO3 ----> NaNO3 + AgI
The net ionic equation is Ag+(aq) + I- --> AgI(s) The sodium (Na+) and nitrate (NO3-) are spectators as always.
A precipitate of yellow Lead iodide and Sodium nitrate are formed
Produces yellow Lead(II) iodide and Sodium nitrate
Na2S + Cu(NO3)2 -> 2NaNO3 + CuS
The chemical equation is: Na+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + Na+[NO3]- (aq)