in aqueous medium ppts. of copper iodide are formed which are converted into cuprous iodide and free iodine in a short time. 2NaI + Cu(NO3)2 = CuI2 + 2NaNO3 2CuI2 = Cu2I2 + I2
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The chemical equation is: Na+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + Na+[NO3]- (aq)
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
Equation: NaI + AgNO3 ----> NaNO3 + AgI
the equation for sodium nitrate and copper III iodide can be given below.Cu I 2 +2 Na No3 ->I (NO3)2 + 2NaI. this is the balance reaction for the above.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The chemical equation is: Na+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + Na+[NO3]- (aq)
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
Equation: NaI + AgNO3 ----> NaNO3 + AgI
The net ionic equation for the reaction between sodium iodide (NaI) and silver nitrate (AgNO3) when a precipitate is formed is: 2Ag+ + 2I- -> Ag2I (s) This equation represents the formation of silver iodide (AgI) precipitate when silver cations react with iodide anions.
The reaction between sodium nitrate and copper nitrate is a double displacement reaction. When mixed, they exchange ions to form sodium nitrate and copper nitrate. The overall reaction equation is NaNO3 + Cu(NO3)2 -> 2NaNO3 + Cu.
The filtrate of lead nitrate and sodium iodide would contain soluble sodium nitrate and insoluble lead iodide. Lead iodide is a yellow solid that precipitates out of the solution, while sodium nitrate remains in the filtrate as it is soluble in water.
The formula for lead iodide is PbI2 and the formula for sodium nitrate is NaNO3.
When reactants lead(II) nitrate and sodium iodide are combined, a double displacement reaction occurs. Lead(II) iodide (insoluble in water) and sodium nitrate are formed, leading to a white precipitate of lead(II) iodide and a solution of sodium nitrate.
When sodium nitrate (NaNO3) reacts with potassium iodide (KI), it forms sodium iodide (NaI) and potassium nitrate (KNO3). This reaction is a double replacement reaction, where the positive ions from each compound switch places. The chemical equation for this reaction is: NaNO3 + KI → NaI + KNO3.