2c8h18 + 25o2--> 16co2 + 18h2o
Octane + Oxygen ----> Carbon dioxide + Water2 C8H18 + 25 O2 ----> 16 CO2 + 18H2O
C8 h18
2C8H18 + 17O2 --> 16CO + 18H2O C8H18 + 8.5O2 --> 8CO + 9H2O half equation, halfs can be used in combustion.
Carbon dioxide and water. =)
The combustion reaction of octane is:2 C8H18 + 25 O2 = 16 CO2 + 18 H2OSo, the number of oxygen molecules is 25.The isomer trimethylpentane is used as standard in octane rating: the end of the scale at 100.
For complete combustion, the equation is C6H12 + 12 O2 = 6 CO2 + 6 H2O.
This is a typical combustion reaction in that it involves a hydrocarbon reacting with oxygen. The products of combustion reactions are always carbon dioxide and water, just in varying quantities.
The complete combustion of ethanol in oxygen proceeds according to the balanced equation C2H6O + 3 O2 -> 2 CO2 + 3 H2O.
helium is chemically inert and doesn't undergo combustion reaction
This equation, for complete combustion, is C8H16 + 12 O2 => 8 CO2 + 8 H2O. (The first formula in the equation is a molecular formula for ethylcyclohexane.)
C53+H778=undecane
Octane and water do not react and so there is not an equation.