Na3PO4+CuBr2=Cu3(PO4)2+NaBr
PO4 has a charge of -3 and Cu (in this equation as shown by CuBr2) has a charge of +2, when they combine you switch the chareges and add them on as subscripts to each other. Na and Br have the opposite charges, -1 and +1, so you don't have to add them to the equation.
The final solution of Na3PO4 + CuBr2 would contain NaBr and Cu3(PO4)2 precipitate as products. Hints:
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.
Mixing NaOH and Na3PO4 will yield Na2HPO4 (sodium hydrogen phosphate) and Na3PO4 (trisodium phosphate) as products.
The balanced equation for the reaction between zinc (Zn) and copper (II) bromide (CuBr2) is: Zn + CuBr2 → ZnBr2 + Cu
The compound formed by Na+ and PO43- ions is sodium phosphate, which has the chemical formula Na3PO4.
The balanced equation for the reaction of calcium nitrate solution (Ca(NO3)2) with sodium phosphate solution (Na3PO4) is: 3Ca(NO3)2 + 2Na3PO4 -> Ca3(PO4)2 + 6NaNO3
Mixing NaOH and Na3PO4 will yield Na2HPO4 (sodium hydrogen phosphate) and Na3PO4 (trisodium phosphate) as products.
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.
The balanced equation for the reaction between zinc (Zn) and copper (II) bromide (CuBr2) is: Zn + CuBr2 → ZnBr2 + Cu
The compound formed by Na+ and PO43- ions is sodium phosphate, which has the chemical formula Na3PO4.
The reaction between H3PO4 (phosphoric acid) and NaOH (sodium hydroxide) can be represented by the following equation: H3PO4 + 3NaOH → Na3PO4 + 3H2O. Here, one molecule of phosphoric acid reacts with three molecules of sodium hydroxide to produce one molecule of sodium phosphate and three molecules of water.
Na3PO4 and CuSO4
3, 2, 2, 1
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
The chemical reaction is:H3PO4 + 3 NaOH + Na3PO4 + 3 H2O
Yes, you need to put the PO4 in parentheses and add a 3 subscript to indicate that there are 3 phosphate ions in the compound. The product of Na3PO4 + NiCl2 would be Ni3(PO4)2 + 6NaCl.
The reaction is:3 MgSO4 + 2 Na3PO4 = Mg3(PO4)2 + 3 Na2SO4
No. The mole of solution is equal to mole of solute plus mole of solvent (solVENT !, not solution)