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Answered 2009-12-04 15:28:46

Li2CO3: Lithium is a monovalent cation and carbonate is a divalent anion, so that two lithium ions are required for each carbonate ion.

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Yes, lithium carbonate is an ionic compound with the formula unit Li2CO3.


The formula for lithium hydrogen carbonate is LiHCO3.


Lithium carbonate is an ionic compound.


Lithium Carbonate is the name for the ionic compound Li2CO3.


The ionic compound lithium phosphide would have a formula of Li3P.


The chemical formula for the compound formed by lithium and oxygen is Li2O, and is named lithium oxide.


Strontium chloride is a compound of lithium and chlorine with the formula SrCl2. Lithium chloride is a compound of lithium and chlorine with the formula LiCl.



Lithium carbonate is a chemical compound with the formula Li2CO3. This colorless polymer is widely used in the processing of metal oxide and has received attention for its use in psychiatry.


The formula of the compound lithium oxide is Li2O.



The chemical formula of lithium carbonate is LiHCO3.




The formula for the compound between Lithium and Sulfur is Li2S because Lithium has a +1 charge while Sulfur has a -2. So for it to be stable, there needs to be two Lithium atoms attached to one Sulfer.


Li+ is the lithium ion. CO32- is the carbonate ion. Li2CO3 is lithium carbonate.


The compound formed from lithium and oxygen is lithium oxide, with the formula unit Li2O.


Lithium fluoride is the compound formed as a result of this reaction: LiF is the formula.


lithitum is an element not a compound. lithium makes compounds with other elements such as lithium carbonate and lithium hydroxide.


To work out the mass of one element within a compound (ie the mass of Lithium in Lithium Carbonate), first work out the RFM (Relative Formula Mass) of the compound. To do this, look on the periodic table (PT) & add up the RAM (Relative Atomic Mass) of all of the atoms in the compound (the RAM is the larger of the 2 numbers in each box on the PT). So, if the formula for one molecule of Lithium Carbonate is Li2CO3, then the RFM is Li + Li + C + O + O + O = 7 + 7 + 12 + 16 + 16 + 16 = 74 Next work out what percentage of the compound is the element you want to know. So, Lithium accounts for 14 (2 Lithiums = 7 x 2) out of every 74 grams of Lithium Carbonate. As a percentage, this is ( 14 / 74 ) x 100 = 18.9 %. So, 18.9% of 1.55g [ ( 1.55 / 100 ) x 18.9 ] = 0.29g So there is 0.29g of Lithium is 1.55g of Lithium Carbonate.





Lithium and fluorine react together to form lithium fluoride which is an ionic compound.


Lithium bromide, LiBr, is prepared by the treatment of lithium carbonate with hydrobromic acid



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