To work out the mass of one element within a compound (ie the mass of Lithium in Lithium Carbonate), first work out the RFM (Relative Formula Mass) of the compound.
To do this, look on the Periodic Table (PT) & add up the RAM (Relative Atomic Mass) of all of the atoms in the compound (the RAM is the larger of the 2 numbers in each box on the PT).
So, if the formula for one molecule of Lithium Carbonate is Li2CO3, then the RFM is Li + Li + C + O + O + O = 7 + 7 + 12 + 16 + 16 + 16 = 74
Next work out what percentage of the compound is the element you want to know.
So, Lithium accounts for 14 (2 Lithiums = 7 x 2) out of every 74 grams of Lithium Carbonate. As a percentage, this is ( 14 / 74 ) x 100 = 18.9 %.
So, 18.9% of 1.55g [ ( 1.55 / 100 ) x 18.9 ] = 0.29g
So there is 0.29g of Lithium is 1.55g of Lithium Carbonate.
it is simply 1.55 multiply by (18.8 /100)=0.2914 grams
Sodium cations and carbonate anions.
234 grams :)
the answer is 2
Calcium carbonate.
Carbonate, CO32-
By definition, carbon and oxygen are present in all carbonates. A molecule is a carbonate if it contains a carbonate group (CO3), which itself contains carbon and oxygen.
Calcium carbonate contains Ca2+ cation and sulfuric acid contains H+(aq) cations. When they react CaCO3 + H2SO4 -> CO2 +CaSO4 +H2O
sodium carbonate
Sodium carbonate contains two ionic bonds, between one Na and CO3 and the other Na and CO3, because in water it brakes down to 2Na+ and CO3- ions.
Sodium cations and carbonate anions.
88
The chemical formula for the compound potassium carbonate is K2CO3. The elements potassium, carbon and oxygen are present. They are present in the ratio 2:1:3.
the barium ion Ba2+ and the carbonate ion CO32+
Li+, F-.
234 grams :)
Determination of sodium in the analyzed material or Determination of carbonate (or CO2)
The formula contains the chemical symbols and tells us what the elements are. As an example Calcium Carbonate is CaCO3 and shows that Calcium, Carbon and Oxygen are present.