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Sulfuric acid plus copper (II) nitrate yields nitric acid plus copper (II) sulfate. Sulfuric acid plus copper (I) nitrate yields nitrous acid plus copper (I) sulfate.
Fe + 2 CuNO3 = Fe(NO3)2 + 2 Cu.
Fe + CuSO4 --> FeSO4 + Cu Iron + Copper (II) Sulfate yields Iron (II) Sulfate and Copper
Yes, but your formula for copper II nitrate is incorrect. It should be Cu(NO3)2. The correct equation is Cu(NO3)2 + 2HCl --> CuCl2 + 2HNO3.
As copper is more reactive than silver copper will displace silver and will become copper nitrate and silver is left by its own from the reaction
If the copper nitrate formed is copper (I) nitrate, the equation balances with one atom of each metal and one formula weight of each nitrate. If the copper nitrate formed is copper (II) nitrate, the balanced equation is: 2 AgNO3 + Cu -> 2 Ag + Cu(NO3)2.
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Sulfuric acid plus copper (II) nitrate yields nitric acid plus copper (II) sulfate. Sulfuric acid plus copper (I) nitrate yields nitrous acid plus copper (I) sulfate.
FeO+LiNO3------->LiO+FeNO3it is already balanced ..............................
Fe + 2 CuNO3 = Fe(NO3)2 + 2 Cu.
Fe + CuSO4 --> FeSO4 + Cu Iron + Copper (II) Sulfate yields Iron (II) Sulfate and Copper
The reaction is:Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag
Yes, but your formula for copper II nitrate is incorrect. It should be Cu(NO3)2. The correct equation is Cu(NO3)2 + 2HCl --> CuCl2 + 2HNO3.
As copper is more reactive than silver copper will displace silver and will become copper nitrate and silver is left by its own from the reaction
Na2S + Cu(NO3)2 -> 2NaNO3 + CuS
Copper Carbonate + Nitric Acid
The iron is higher in they reactivity scale than copper , Therefore the copper will be replaced by iron to make iron sulfate and copper by itself.