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Hf values are used to find products-reactants. 4(-393.5)+6(-285.8)=-3288.8, sum of products, minus 2(-84)= -3120.8

divide by 2 since its two moles and you only want one= -1560.4

divide by the molar mass of ethane, 30.07, and you get -51.892.

make it positive because fuel values are positive and you get 51.892 as your final answer

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Q: What is the fuel value of ethane in kilojoules per gram of ethane?
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