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RR since sickle cell is a recessive so a dominant trait means a non sicklier. If they have the trait it will be Rr which is heterozygous but RR is homozygous non sicklier.

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Q: What is the genotype of a person that is homozygous non sicklier?
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How many different non repeating allele combinations can appear in the gametes of a person with the genotype AABBCc?

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if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children


What percentage of the possible types of offspring had the same phenotype as the parents?

Hey there. To answer this accurately, i would need to know the genotypes of both parents. I'll show you a trick that works them out in a flash. A phenotype is the result of a genotype, which is the result of 2 alleles. Say if both parents were HOMOZYGOUS for brown hair, with their genotype would be BB, BB. Use a trick called a punnet square to answer this; _|B |B | B|BB|BB| <-- not the best punnet square, but the top row shows the first parents B|BB|BB| genotype (BB) and the side shows the second's. (BB) The cross of this shows all the children will have brown hair, as inherited from each parent. If the Mother had HOMOZYGOUS brown hair (BB), and the father had HETEROZYGOUS brown hair (Bb) the results would be 100% Brown hair too, because the brown hair gene (B) is dominant over the non brown hair gene (b). Below; _|B |B | B|BB|BB| <--- this shows the cross gives a 50% chance to be Homozygous for brown b|Bb|Bb| hair but 50% heterozygous for brown hair, but carrying a non- brown hair gene. If we cross 2 heterozygous parents, the results are shown: _|B |b | B|BB|Bb| b|bB|bb| <----- This shows the child has a 75% chance of having brown hair (either (BB or bB, Bb) and 25% of being non-brown (bb)). This can be used in any gene cross, but you must keep in mind that one gene will be dominant and one will be recessive. I used the brown hair gene as an example here, as I don't know whether it may be dominant or recessive to other hair colours. Also, if you were after a global statistic, I wouldn't know. I hope this helps you. Fletch


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Related questions

How many different non repeating allele combinations can appear in the gametes of a person with the genotype AABBCc?

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Hey there. To answer this accurately, i would need to know the genotypes of both parents. I'll show you a trick that works them out in a flash. A phenotype is the result of a genotype, which is the result of 2 alleles. Say if both parents were HOMOZYGOUS for brown hair, with their genotype would be BB, BB. Use a trick called a punnet square to answer this; _|B |B | B|BB|BB| <-- not the best punnet square, but the top row shows the first parents B|BB|BB| genotype (BB) and the side shows the second's. (BB) The cross of this shows all the children will have brown hair, as inherited from each parent. If the Mother had HOMOZYGOUS brown hair (BB), and the father had HETEROZYGOUS brown hair (Bb) the results would be 100% Brown hair too, because the brown hair gene (B) is dominant over the non brown hair gene (b). Below; _|B |B | B|BB|BB| <--- this shows the cross gives a 50% chance to be Homozygous for brown b|Bb|Bb| hair but 50% heterozygous for brown hair, but carrying a non- brown hair gene. If we cross 2 heterozygous parents, the results are shown: _|B |b | B|BB|Bb| b|bB|bb| <----- This shows the child has a 75% chance of having brown hair (either (BB or bB, Bb) and 25% of being non-brown (bb)). This can be used in any gene cross, but you must keep in mind that one gene will be dominant and one will be recessive. I used the brown hair gene as an example here, as I don't know whether it may be dominant or recessive to other hair colours. Also, if you were after a global statistic, I wouldn't know. I hope this helps you. Fletch


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