Please indicate the purpose of adding the copper sulphate and resubmit your question.
CuSO4 +2 NaOH = Cu (OH) 2 ↓ + Na2SO4 Cu (OH) 2 blue flocculent precipitate
Na3PO4
NaNO3 and water
No. BaSO4 is a salt. NaOH is a base.
COPPER SULPHATE CRYSTAL.. CuSO4.5H2O + H2SO4 ___________ CuSO4 + 5H2O in the above reaction sulphric acid acts as a dehydrating agent..
Copper and carbon along with oxygen make up copper(II) carbonate. However you cannot make it simply by mixing them together. A possible pathway might be to get to sodium carbonate perhaps CO2 + NaOH might be the way and then make some copper sulfate by reacting it with H2SO4, mix your sodium carbonate solution with copper sulfate solution and copper carbonate should precipitate out.
The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
CuSO4 +2 NaOH = Cu (OH) 2 ↓ + Na2SO4 Cu (OH) 2 blue flocculent precipitate
Biuret reagent is made up of sodium hydroxide and copper sulphate.
No, sodium bisulfate (NaHSO4) cannot be prepared by mixing sodium sulfate (Na2SO4) with hydrochloric acid (HCl), because both sulfuric acid and hydrochloric acids are "strong" acids (the H+ will completely dissociate from the anion in solution). If there is enough sodium to bind to the sulfate ions (2 sodiums per sulfate), then the H+ ions will gladly let them do so. So, NaHSO4 must be produced from sulfuric acid (H2SO4). One method is adding just enough sodium hydroxide (NaOH) so that the number of sodium ions is equal to the number of sulfate ions: H2SO4 + NaOH ---> NaHSO4 + H2O The sodium will displace one of the hydrogens, but there's not enough to displace both.
Na3PO4
Sulfuric acid reacts violently with NaOH, producing sodium sulfate and water and lots of heat!
NaNO3 and water
No. BaSO4 is a salt. NaOH is a base.
The concentration is 12,8 g/L NaOH.
COPPER SULPHATE CRYSTAL.. CuSO4.5H2O + H2SO4 ___________ CuSO4 + 5H2O in the above reaction sulphric acid acts as a dehydrating agent..
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================