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3.90x10^24 atoms To arrive at an answer in units of carbon atoms, first we must cancel out the grams by diving 84.3g C2H2 by the molar mass of C2H2 (26.038g/mol). This molar mass is calculated by adding the masses of 2 carbon atoms (12.011g/mol) and 2 hydrogen atoms (1.008g/mol). This renders units of moles of ethyne. Next multiply by Avagadro's number (6.022x10^23 atoms/mol) to cancel the moles of ethyne and reach atoms of ethyne. Finally, because there are 2 carbon atoms in C2H2, multiply by 2 atoms Carbon/1 atom C2H2 to reach the final answer of 3.90x10^24 atoms of Carbon. This answer has been rounded to three significant figures because the lowest known value of significant figures throughout the calculations was three (84.3). The entire process is as follows: 84.3g C2H2 x (1 mol C2H2)/(26.038 g C2H2) x (6.022x10^23 atoms C2H2)/(1 mol C2H2) x (1 atoms C2H2)/(2 atom C) = 3.90x10^24 atoms C
In this compound, the carbon atoms undergo sp3 hybridization.
Hybridisation is given by the formula: H=1/2{ V + X - C + A} V=no of valence electrons in central atom X=no of monovalent atoms around the central atom C= +ve charge on cation A= -ve charge on anion C2H2 is ethyne and the structure is a triple bond between te carbon atoms then each hydrogen is bonded to one of the carbons. So it looks like H-C[tb]C-H ([tb] denotes triple bond). The hybridization for each of the carbon atoms is sp.
one carbon atom in C2H2 forms four bonds one bond with hydrogen and a triple bond with other carbon.
sp
3.90x10^24 atoms To arrive at an answer in units of carbon atoms, first we must cancel out the grams by diving 84.3g C2H2 by the molar mass of C2H2 (26.038g/mol). This molar mass is calculated by adding the masses of 2 carbon atoms (12.011g/mol) and 2 hydrogen atoms (1.008g/mol). This renders units of moles of ethyne. Next multiply by Avagadro's number (6.022x10^23 atoms/mol) to cancel the moles of ethyne and reach atoms of ethyne. Finally, because there are 2 carbon atoms in C2H2, multiply by 2 atoms Carbon/1 atom C2H2 to reach the final answer of 3.90x10^24 atoms of Carbon. This answer has been rounded to three significant figures because the lowest known value of significant figures throughout the calculations was three (84.3). The entire process is as follows: 84.3g C2H2 x (1 mol C2H2)/(26.038 g C2H2) x (6.022x10^23 atoms C2H2)/(1 mol C2H2) x (1 atoms C2H2)/(2 atom C) = 3.90x10^24 atoms C
In this compound, the carbon atoms undergo sp3 hybridization.
Hybridisation is given by the formula: H=1/2{ V + X - C + A} V=no of valence electrons in central atom X=no of monovalent atoms around the central atom C= +ve charge on cation A= -ve charge on anion C2H2 is ethyne and the structure is a triple bond between te carbon atoms then each hydrogen is bonded to one of the carbons. So it looks like H-C[tb]C-H ([tb] denotes triple bond). The hybridization for each of the carbon atoms is sp.
The carbon atoms are sp2 hybridised.
one carbon atom in C2H2 forms four bonds one bond with hydrogen and a triple bond with other carbon.
The carbon atoms are sp2 hybridised.
sp3. The carbon atoms are tetrahedrally positioned around the central carbon atom.
There are 4 carbon atoms, which each individually act as a central atom since they are surrounded entirely by the hydrogen atoms. Each carbon forms 4 sigma bonds, therefore, each carbon atom has a hybridization state of sp^3.
Two elements Carbon and Hydrogen in acetylene, C2H2, two atoms of each.
When a carbon atom is linked to 4 other atoms and those atoms are arranged in space at the corners of a tetrahedron (bond angle 109.5 0), then the hybridisation is sp3.
There is no central atom in P4O6. The molecule has a tetrahedron of P atoms where the P atoms are helf together by briding oxygen atoms.