+2. As it must balance the -2 charge of the Sulphate (SO4)
+2, bcoz oxidation state of SO4 ion is -2 n as the total charge on the compound is 0, Mn should have equal +ve charge to nullify it
they can be 2+, but methinks they can be something else, too
The molecule is neutral. The oxidation number of manganese in MnO2 is 4+.
+6 for sulphur
6
-2 oxidation state
Mg = +2 oxidation state P = +5 oxidation state O = -2 oxidation state
O = -2 oxidation state P = +5 oxidation state
+5 oxidation state
-2 oxidation state
In all sulphate compounds 'S' is in 6+ oxidation state.
MnSO4 aplications in Agriculture
3
MnO2 manganese(IV) oxide. Oxygen has a -2 oxidation state (oxidation state is a better term here as oxidation number is better used for complexes- they give the same answer for this compound)
MnSO4 is the only one that directly reacts with O2 at BOD?With alkaline: MnSO4 + 2OH = MnOH2 +SO44Mn(OH)2 + 2 H20 + O2 = 4 Mn(OH)3
I must have the same sheet as you as I have the exact same question. Okay, The RFM of Manganese (Mn) is 54.9 The RFM of MnSO4 4H20 is 223 The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 % 0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3 24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.
Oxidation number of MN is +4. Oxidation number of Oxygen is -2
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
KMnO4 is a neutral molecule, so the oxidation numbers of each element must all add to zero.O is 2- and there are 4 of them = -8 K is 1+ so one K = +1 This is a total of -7, therefore Mn MUST BE 7+ oxidation number.
O.S of Mn = 3+ O.S. of Cl = 7+ O.S. of O = 2-
It is rarely, but manganese can show the valence 5+.
The oxidation number of Mn in manganese VII oxide is +7.