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I must have the same sheet as you as I have the exact same question.

Okay,

The RFM of Manganese (Mn) is 54.9

The RFM of MnSO4 4H20 is 223

The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 %

0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3

24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g

Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.

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Wiki User

13y ago
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AnswerBot

6mo ago

In one mole of hydrated manganese II sulphate, there is one mole of manganese atoms. Therefore, in 0.1 moles of hydrated manganese II sulphate, there will be 0.1 moles of manganese.

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Q: How many moles of manganese are contained in 0 point 1 moles of hydrated manganese II sulphate MnSO4 4H2O which has an RFM of 223?
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