-- We can't say anything about the velocity, because we don't know anything about the
horizontal motion of the ball. With the information included in the question, we can only
be sure of how the vertical component of velocity behaves.
-- At the maximum altitude of the ball, there's the instant where its vertical speed
changes from upward to downward. At that instant, its vertical speed is zero.
0 is the ball is bouncing straight up and down.
The ball has the highest gravitational potential energy when it is at its highest point in the air, as that is when it has a velocity of zero and is up the highest.
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
Yes, assuming the ball has elasticity and you haven't exceeded the height where the ball, when dropped, reaches terminal velocity.
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
Placing a question mark at the end of a list of expressions or numbers does not make it a sensible question. Try to use a whole sentence to describe what it is that you want answered.One possible answer is that it has reached the maximum altitude of its trajectory.
The ball has the highest gravitational potential energy when it is at its highest point in the air, as that is when it has a velocity of zero and is up the highest.
Kinetic energy is at its maximum when the velocity of the ball is greatest. This will occur immediately upon release. Air resistance will slow the ball from this point and unless the ball falls back past its original starting height, it will never achieve a velocity greater than that with which it starts.
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
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Yes, assuming the ball has elasticity and you haven't exceeded the height where the ball, when dropped, reaches terminal velocity.
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
As velocity never exceeds the velocity of light.... so i hope a man running with the velocity of light will not be able to throw a ball with any velocity.......... we may get the maximum n minimum velocity with which that can be thrown mathematically that we may get it to be zero................
force = mass * acceleration = 2 * -9.82 = -19.64 newtons work done = force * distance = -19.64 * 5.092 metres = -100 joules
96.03 ft/s = 29.27 m/s = 65.5 mph = 105 kph = velocity of the ball
Placing a question mark at the end of a list of expressions or numbers does not make it a sensible question. Try to use a whole sentence to describe what it is that you want answered.One possible answer is that it has reached the maximum altitude of its trajectory.
all objects accelerate to earth at 9.8 m/s/s until it reaches its terminal velocity.
0.82 metres.