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How many bits are stored by a 256 x 4 memory chip can this chip be specified as 128 byte memory?
256x4=1024 bits are stored.128x8=1024 ,yes this chip can be specified as 128 byte
Maximum memory address space that the processor can access directly if it is connected to a 16-bit memory?
Max. memory address space= 216 X 2 bytes = 128 Kbytes
What is the smallest computer memory chip available?
Sandisk has created a memory chip that holds 128 gigabytes of flash memory, yet is only nineteen nanometers. This beat the previous record of twenty nanometers, held by Micron.
How many bits are bit addressable in the internal RAM and what is the range of the address?
Of the 128-byte internal RAM of the 8051, only 16 bytes are bit-addressable. The rest must be accessed in byte format. The bit-addressable RAM locations are 20H to 2FH.
What is the smallest decimal number that can be represented by one byte?
-127 or -128
In what class is the ip address 169.45.66.200?
Class B includes anything that starts with binary "10", or in decimal, 128-191 for the first byte.Class B includes anything that starts with binary "10", or in decimal, 128-191 for the first byte.Class B includes anything that starts with binary "10", or in decimal, 128-191 for the first byte.Class B includes anything that starts with binary "10", or in decimal, 128-191 for the first byte.
How do you interface a code memory of 128 KBytes to a controller having 16 address lines?
use bank-switching, or (slower) a shift register.
What is the size of byte in java?
The size of a byte primitive is 8-bits.
How many IC required to obtain 2048 8 memory using 128 8 memory chip?
2048/128 = number of chips.
What is the largest posistive number that can be represented using 1 byte?
If the byte represents a signed number, values commonly go from minus 128 to plus 127. If the byte represents an unsigned number, values commonly go from 0 to 255.
Which address types are 128 bits in length?
IPv6 address
How many 128 x 8 RAM chips are needed to provide a memory capacity of 4096x16?
128x8=128 bytes 4096x16=4069x(8x2)=4096x2 bytes; hence, chips required, 4096*2/128=64; ans=64.
