In the reaction MgCI2 plus 2KOH Mg(OH)2 plus 2KCI if 6 moles mgci2 are added to 6 moles koh which is the limiting reagent?

Answer 1

MgCl2 would be the limiting reagent

Answer 2

MgCl2

Answer 3

MgCl2 + 2KOH ==> Mg(OH)2 + 2KClLooking at this balanced equation, one sees that every ONE mole of MgCl2 reacts with TWO moles of KOH. Thus, the mole ratio is 1 : 2. Therefore 1 mole MgCl2 is added to 3 moles KOH, there will be plenty of KOH since only 2 moles would be needed. Thus MgCl2 would be limiting.

Answer 4

Write the BALANCED reaction eq'n

2KOH + MgCl2 = 2KCl + Mg(OH)2

So in the molar ratios 2 moles KOH reacts with 1 mole MgCl2

Since we have 6 moles of each

Then 6 moles (KOH) only requires 3 moles MgCl2 ( but we have 6 moles)

So KOH is the limiting reactant leaving 3 moles MgCl2 unreacted,

Answer 5

The limiting reagent is potassium hydroxide.

Answer 6

KOH

Answer 7

MgCl2