2 Na OH + CuCl2
Cu(NO3)2(aq) + 2 NaOH(aq) à Cu(OH)2(s) + 2 NaNO3(aq)­
Since copper (I) chloride has only limited solubility in water I will assume you mean copper (II) chloride, CuCl2. Then the ions will be Cu2+ and Cl-.
This is an addition reaction that is also a complexing reaction. The ammonia complexes the copper and acts as a ligand. Tetra-amine Copper Chloride is formed which is a deep inky blue color. [Cu(NH3)4]2+ [Cl-]2 + 4H2O
Metallic copper does not react with sodium hydroxide. But if sodium hydroxide is added into a solution of copper ions, it would form Copper(II) Hydroxide. It is a precipitate which is insoluble in water.
Copper I Chloride is CuCl and Copper II Chloride CuCl2
In this reaction, aluminum is the limiting reagent because it will be fully consumed before all the copper sulfate is used up. The aluminum will react with the copper sulfate to form aluminum sulfate and copper metal. Once all the aluminum has reacted, the reaction will stop.
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
You would write the balanced chemical equation as: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction involves the double displacement of ions between copper (II) chloride and sodium hydroxide to form copper (II) hydroxide and sodium chloride.
To determine the limiting reactant, we need to compare the moles of each reactant. First, calculate the moles of aluminum and copper sulfate separately. Then, determine the mole ratio between them and see which reactant is present in lower amount compared to the stoichiometric ratio. The reactant that is present in lower moles is the limiting reactant.
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
When cobalt (II) chloride reacts with sodium hydroxide, cobalt (II) hydroxide is formed. The reaction can be represented by the chemical equation: CoCl2 + 2 NaOH -> Co(OH)2 + 2 NaCl.
Biuret reagent is made up of sodium hydroxide and copper sulphate.
Atacamite is a green copper(II) chloride hydroxide mineral which is polymorphous with botallackite.
Cu(NO3)2(aq) + 2 NaOH(aq) à Cu(OH)2(s) + 2 NaNO3(aq)­
The product is copper ii chloride alongwith water, CuO + 2HCl = CuCl2 + H2O
When barium chloride and sodium hydroxide are added to copper nitrate, a white precipitate of barium nitrate forms due to the reaction between barium chloride and sodium nitrate. The copper ions in the solution remain unchanged as they do not react with barium chloride or sodium hydroxide under normal conditions.
efflorescent- washing soda, copper sulphate, glauber salt deliquescent -calcium chloride, sodium hydroxide, iron3 chloride