2 Na OH + CuCl2
Cu(NO3)2(aq) + 2 NaOH(aq) à Cu(OH)2(s) + 2 NaNO3(aq)­
Since copper (I) chloride has only limited solubility in water I will assume you mean copper (II) chloride, CuCl2. Then the ions will be Cu2+ and Cl-.
This is an addition reaction that is also a complexing reaction. The ammonia complexes the copper and acts as a ligand. Tetra-amine Copper Chloride is formed which is a deep inky blue color. [Cu(NH3)4]2+ [Cl-]2 + 4H2O
Metallic copper does not react with sodium hydroxide. But if sodium hydroxide is added into a solution of copper ions, it would form Copper(II) Hydroxide. It is a precipitate which is insoluble in water.
Copper I Chloride is CuCl and Copper II Chloride CuCl2
usually it will be copper sulfate as a limiting reagent
Copper chloride + Sodium hydroxide --> Copper hydroxide + sodium chloride
CuCl2+NaOH= Cu(OH)2+Na2Cl
Aluminum would be the limiting reagent
The compound copper (III) chloride doesn't exist !
The insoluble in water copper(II) hydroxide is formed.
Biuret reagent is made up of sodium hydroxide and copper sulphate.
Atacamite is a green copper(II) chloride hydroxide mineral which is polymorphous with botallackite.
Cu(NO3)2(aq) + 2 NaOH(aq) à Cu(OH)2(s) + 2 NaNO3(aq)­
The product is copper ii chloride alongwith water, CuO + 2HCl = CuCl2 + H2O
When you mix the solutions of Sodium Hydroxide and barium chloride then a double replecement occurs.2 NaOH + BaCl2 = 2 NaCl + Ba(OH)2
efflorescent- washing soda, copper sulphate, glauber salt deliquescent -calcium chloride, sodium hydroxide, iron3 chloride