9,85x10 to the 24 of methanol (CH3OH) molecules have a mass of 52,405 g.
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
192.678 grams CH3OH
I am assuming that the question is: what is the mass, in grams, of 9.93x1024 molecules of methanol (CH3OH). For any question concerning mass and a chemical, we must find the molecular mass by adding the atomic masses from the periodic table: C=12.0g 4H= 4 x 1.01 = 4.04g O=16.0g Total: 32.0g/mole Now, how many moles is 9.93x1024 molecules, if one mole is 6.02x1023? (9.93x1024 ) / (6.02x1023) = 15.5 moles. So, 15.5 moles x 32.0g/mole = 496g.
The molar mass of the lightest alcohol, methanol, is 32.04 grams per mol. No alcohol has a molar mass of 4.75 grams. To find the molar mass of a substance, you sum the mass of every atom that makes up your compound. For methanol, you add the mass of three hydrogens, a carbon, and an oxygen atom. An alcohol group, more properly a "hydroxyl," consists of an oxygen and a hydrogen and contributes about 17 grams per mol to the molar mass (about 16 g/mol for an oxygen atom and 1 for a hydrogen). Hope this helps!
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
8.20g of carbon monoxide, how many grams of methanol will be produced?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
192.678 grams CH3OH
The mass is 483,62 g.
I am assuming that the question is: what is the mass, in grams, of 9.93x1024 molecules of methanol (CH3OH). For any question concerning mass and a chemical, we must find the molecular mass by adding the atomic masses from the periodic table: C=12.0g 4H= 4 x 1.01 = 4.04g O=16.0g Total: 32.0g/mole Now, how many moles is 9.93x1024 molecules, if one mole is 6.02x1023? (9.93x1024 ) / (6.02x1023) = 15.5 moles. So, 15.5 moles x 32.0g/mole = 496g.
The answer is 50,196 g.
--> number of moles of CH3OH = mass/molar mass 22/(12+3+16+1) = 0.6875 moles --> number of mole = conc multiply by volume(indm3) number of moles divided by volume[indm3] = concentration 0.6875/[.25] = 2.75 mol/dm3
The molar mass of the lightest alcohol, methanol, is 32.04 grams per mol. No alcohol has a molar mass of 4.75 grams. To find the molar mass of a substance, you sum the mass of every atom that makes up your compound. For methanol, you add the mass of three hydrogens, a carbon, and an oxygen atom. An alcohol group, more properly a "hydroxyl," consists of an oxygen and a hydrogen and contributes about 17 grams per mol to the molar mass (about 16 g/mol for an oxygen atom and 1 for a hydrogen). Hope this helps!
Methanol, CH4O, has a molar mass of 32g (12g+4.0g+16g)* *note this is only rounded to two sig figs, since the mass of elements are usually rounded to the tenths place. Next, simply use dimensional analysis: 1ml/22.4L X 32g. you should get the right answer by doing the steps shown above.
The simplest form of the molecular formula for methanol {note corrected spelling} is CH4O, and its gram molecular mass is 32.04. By definition therefore, a mass of Avogadro's Number of molecules contains 32.04 grams. Avogadro's Number is about 6.022 X 1023. Therefore, 9.47 X 1024 molecules of methanol contains [(9.47 X 1024)/(6.022 X 1023)]32.04 or 504 grams, to the justified number of significant digits.