The mass is 483,62 g.
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
8.20g of carbon monoxide, how many grams of methanol will be produced?
The mass of 5,2.e10 molecules of fluorine (F2) is 32,809.10e-13 g.
A mole of a substance contain 6,022 140 857.10ex23 (number of Avogadro - NA ) molecules.A mass (in grams) contain a number of molecules equal to:(given mass x number of Avogadro)/molar mass
The mass is 74,7 mg.
The answer is 50,196 g.
9,85x10 to the 24 of methanol (CH3OH) molecules have a mass of 52,405 g.
The simplest form of the molecular formula for methanol {note corrected spelling} is CH4O, and its gram molecular mass is 32.04. By definition therefore, a mass of Avogadro's Number of molecules contains 32.04 grams. Avogadro's Number is about 6.022 X 1023. Therefore, 9.47 X 1024 molecules of methanol contains [(9.47 X 1024)/(6.022 X 1023)]32.04 or 504 grams, to the justified number of significant digits.
I am assuming that the question is: what is the mass, in grams, of 9.93x1024 molecules of methanol (CH3OH). For any question concerning mass and a chemical, we must find the molecular mass by adding the atomic masses from the periodic table: C=12.0g 4H= 4 x 1.01 = 4.04g O=16.0g Total: 32.0g/mole Now, how many moles is 9.93x1024 molecules, if one mole is 6.02x1023? (9.93x1024 ) / (6.02x1023) = 15.5 moles. So, 15.5 moles x 32.0g/mole = 496g.
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
8.20g of carbon monoxide, how many grams of methanol will be produced?
The mass is 49,06 g.
The molar mass of the lightest alcohol, methanol, is 32.04 grams per mol. No alcohol has a molar mass of 4.75 grams. To find the molar mass of a substance, you sum the mass of every atom that makes up your compound. For methanol, you add the mass of three hydrogens, a carbon, and an oxygen atom. An alcohol group, more properly a "hydroxyl," consists of an oxygen and a hydrogen and contributes about 17 grams per mol to the molar mass (about 16 g/mol for an oxygen atom and 1 for a hydrogen). Hope this helps!
The mass of ammonia is 339,7 g.
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
The mass of 5,2.e10 molecules of fluorine (F2) is 32,809.10e-13 g.