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What is the mass in grams of 9.93x1024 molecules of methanol CH3OH?
Muffinmariah
I am assuming that the question is: what is the mass, in grams, of 9.93x1024 molecules of methanol (CH3OH).
For any question concerning mass and a chemical, we must find the molecular mass by adding the atomic masses from the periodic table:
C=12.0g
4H= 4 x 1.01 = 4.04g
O=16.0g
Total: 32.0g/mole
Now, how many moles is 9.93x1024 molecules, if one mole is 6.02x1023? (9.93x1024 ) / (6.02x1023) = 15.5 moles.
So, 15.5 moles x 32.0g/mole = 496g.
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What is the mass (in grams) of 9.85x10 to the 24 of methanol (CH3OH)?
9,85x10 to the 24 of methanol (CH3OH) molecules have a mass of 52,405 g.
What is the mass in grams of 9.32x1024 molecules of methanol CH3OH?
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
What is the mass of 3.62 X 1024 molecules of CH3OH?
192.678 grams CH3OH
How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 1.5 M CH3OH?
7,207 g methanol are needed.
What is the mass (in grams) of 9.85x10 to the 24 of methanol (CH3OH)?
9,85x10 to the 24 of methanol (CH3OH) molecules have a mass of 52,405 g.
What is the mass in grams of 9.32x1024 molecules of methanol CH3OH?
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
What is the mass of 3.62 X 1024 molecules of CH3OH?
192.678 grams CH3OH
What is the mass (in grams) of methanol of 9.09x1024 molecules of methanol?
The mass is 483,62 g.
How much NH3 is needed to react exactly with 21 grams of CH3OH?
CH3OH + NH3 → CH3NH2 + H2O 32 g of methanol reacts with 17.0 g ammonia 21 g of CH3OH react with 11.0 g NH3
What mass of methanol (CH3OH) is produced when 140.1 g of carbon monoxide reacts with 12.12 g of hydrogen?
8.20g of carbon monoxide, how many grams of methanol will be produced?
How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 1.5 M CH3OH?
7,207 g methanol are needed.
What is the mass(in grams) of 9.401024 molecules of methanol?
The answer is 50,196 g.
How many grams of ch3oh must be added to water to prepare 150 ml of a solution that is 2.0 m ch3oh?
The answer is 9.6 grams.
What is the mass in grams of 9.47 x 1024 molecules of methonal?
The simplest form of the molecular formula for methanol {note corrected spelling} is CH4O, and its gram molecular mass is 32.04. By definition therefore, a mass of Avogadro's Number of molecules contains 32.04 grams. Avogadro's Number is about 6.022 X 1023. Therefore, 9.47 X 1024 molecules of methanol contains [(9.47 X 1024)/(6.022 X 1023)]32.04 or 504 grams, to the justified number of significant digits.
