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0.40 moles of aspirin is 72.1 g.

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8y ago
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11y ago

The gram molecular mass of any compound with the formula C9H8O4 is [9(gram Atomic Mass of carbon) + 8(gram atomic mass of hydrogen ) + 4(gram atomic mass of oxygen)] or 180.1558. This by definition is the mass of Avogadro's Number of molecules. Therefore the mass of 1.40 X 1021 molecules is:

180.1558[(1.40 X 1021 )/6.022 X 1023)] or 4.19 X 10-1 grams, to the justified number of significant digits.

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8y ago

1.56 moles of Aspirin is equal to 281 grams.

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7y ago

The molar mass of aspirin (2-acetoxybenzoic acid), C9H8O4, is 180.157 g/mol.

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7y ago

C9H18O4 has a molar mass of 180.157 g/mol

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3y ago

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Q: What is the mass in grams of 1.40 1021 molecules of aspirin C9H8O4?
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