This can be found using one of the most important constants for chemistry: Avogadro's number.
According to wikipedia, the standard atomic weight of magnesium is 24.3050 grams per mole. Using Avogadro's number, we know there's 6.0221415 × 1023 atoms per mole, so if you divide the standard atomic weight of magnesium by Avogadro's number, you can get number of grams per atom of magnesium (i.e. the mass of a single magnesium atom in grams).
(24.3050 g/mole) / (6.0221415 x 1023 atoms/mole) = 4.03564 g/atom
For this you need the Atomic Mass of Mg. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.
.253 moles Mg × (24.3 grams) = 6.15 grams Mg
By definition, one mole would be the same as the atomic mass. You take the number of moles and multiply it by the atomic mass (divide by one mole for units to cancel). So if you have just 1 mole, the number of grams will just be the atomic mass. Magnesium's atomic mass is 24.31 grams.
For this you need the atomic mass of Mg. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.
.253 moles Mg
1.50 X 1023 atoms of magnesium (1 mole Mg/6.022 X 1023)(24.31 grams/1 mole Mg)
= 6.06 grams magnesium
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The mass in grams of 0,250 moles of Mg is 6,07625 g.
0.458 g apex
Does not convert; milligrams (mg) and grams (g) are measures of weight or mass and mL (milliliters) is a measure of volume.
Magnesium has the molar mass of 24.305 grams per mole. 0.229 moles of Mg has a mass of about 5.57 grams.
1000 mg is a gram so 2.5 mg x 1 gram/1000 mg (note how the mg cancel and we are left with grams)= 25/10000 or 1/400 or a gram which is the same as .0025 grams.
First you need to find the atomic mass of magnesium, 24.3 grams.Then you can do a simple conversion:Grams ÷ Atomic mass = Moles7.5 grams ÷ 24.3 grams = 0.309 moles Mg
1 mg = .001 grams, so .014 mg = 0.000014 grams
I assume you mean 40.59 grams of aluminum. 40.59 grams Al (1 mole Al/26.98 grams)(6.022 X 10^23/1 mole Al) = 9.05978 X 10^23 atoms in that mass aluminum 9.05978 X 10^23 atoms (1 mole Mg/6.022 X 10^23)(24.31 grams/1mole Mg) = 36.57 grams of magnesium
average atomic mass of magnesium is 24.3 g/mole so 24.3 X 1.56 X1021 / 6.02 X1023 = .063 grams
1 gram = 1000 mg
Divide mg by 1,000 to get the same mass in grams. 1,000 mg = 1 gram 900 mg = 0.9 gram
Mg is mega grams (million grams = tonnes) mg is milligrams (thousandths of a gram)3000 Mg is 3000 tonnes or the mass of a small destroyer ship3000 mg is 3 grams or the mass of a coin (slightly more than a US penny)
0.3456 g
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.10.6 grams Mg / (24.3 grams) × (6.02 × 1023 atoms) = 2.63 × 1023 atoms
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.637 grams Mg / (24.3 grams) = .191 moles Mg
According to the US Mint, a quarter has a mass of 5.670 grams, so that is 5670 mg.
Grams is used to measure mass. It is equal to 1000 mg.
0.458 g apex