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How many moles of Na SO4 are in 25.0 of this compound?
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
How many grams are in 3.6 moles of sodium sulfate?
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
What is the difference between the mass of a mole of oxygen and a mole of O2 molecules?
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
What is the mass of one mole of an element that has an atomic mass of 6.94?
This is the third element Lithium: 6.94 g is the mass of 1 mole Li. The mass in grams of one mole of any element is exactly its atomic mass (in a.m.u.)
How many moles are in Na2SO4?
just one. If you were given a mass of Na2SO4, then you could find the number of moles by dividing the mass by the molar mass(total of the mass of all elements from the mass on the periodic table). But Na2SO4 by itself is just one mole.
How many grams of sodium are there in 10.0 grams of sodium sulfate?
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
What is the mass of Na2SO4 needed to make 2.5 L of 2.0 M solution?
how man molecules are there in 450 grams of Na2SO4. the simple formula to determine of mole is NO OF MOL= GIVEN MASS IN gm/MOL:MASS OF COMP: , AND IMOL = 6.02X1023 . SO, 19. 077X1023 molecules are present in 450 grams of Na2SO4.
How many moles of atoms are contained in 2.88g na2 so4?
Full formal set up. 2.88 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(6.022 X 1023/1 mole Na2SO4)(1 mole Na2SO4 atoms/6.022 X 1023) = 0.020 moles of sodium sulfate atoms ------------------------------------------------------( you can see the last two steps are superfluous )
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
How many moles of Na SO4 are in 25.0 of this compound?
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
What is the mole ratio for the following equation MgSO4 2NaCl -- Na2SO4 MgCl2?
This is not a chemical reaction.
What is the mass of 6.0 moles of sodium nitrate (NaNO3)?
1 mole of Na2SO4 is 142.05 or 142.1 when using 4 significant figures
How many grams are in 3.6 moles of sodium sulfate?
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
How many moles of sodium in 5.25 mole of Na2SO4?
5,25 moles (in anhydrous sodium sulphate)
