Mass and the number of mole in a given sample are related quickly with the equation #MOLE = MASS/MOLAR MASS Where the mass is in grams. Now, we know that the number of mole is one, and the molar mass can be found with any Periodic Table - 1.00794 abouts. Now, the equation reads 1 = MASS/1.00794 This can be rearranged through simple mathematics into 1*1.00794 = MASS/1.00794 * 1.00794 Or 1*1.00794 = MASS Since anything multiplied by one is itself, this can be simplified to 1.00794 = MASS So, the mass of 1 mole of Hydrogen is 1.00794 grams. Also, your question was a sentence :p
12.0107 grams per mole; you can read this directly off the periodic table.
In grams? A mole of them (6.02 x 10^23 atoms) weighs only one gram, so one-Avogadro's numberth of a gram.
18.01528 gmol-1.
1.00794 Grams
The mass of 1 mole of H2 will be 2g
water
Mg + 2HCl => MgCl2 + H2 2 moles HCl : 1 mole H2. 2.02 x .5 moles = 1.01 1.01g H2
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
Balanced equation. Mg + H2SO4 -> MgSO4 + H2 ------------------------------------- ( sufuric acid in excess---magnesium limits, drives reaction ) 24 grams magnesium (1 mole Mg/24.31 g)(1 mole H2/1 mole Mg)(2.016 g/1 mole H2) = 1.9 grams of hydrogen gas produced ( can call it 2.0 grams ) --------------------------------------------------
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
1 mol of hydrogen molecule = 1 mol of H2 = molar mass of H2 = 2.0gmol-1 2.0gmol-1 x 1mol = 2.0g 1 mol of hydrogen atom = 1 mol of H = molar mass of H = 1.0gmol-1 1.0gmol-1 x 1mol = 1.0g Hence, they have different masses
Zn + H2SO4 -> ZnSO4 + H2 I assume zinc limits? 31. 8 grams Zn (1 mole Zn/65.41 grams)(1 mole H2/1 mole Zn)(2.016 grams/1 mole H2) = 0.980 grams hydrogen gas
Mg + 2HCl => MgCl2 + H2 2 moles HCl : 1 mole H2. 2.02 x .5 moles = 1.01 1.01g H2
37.66 (g H2) / 2.016 (g/mol H2)= 18.68 mole H2Molar mass of hydrogen: 2.016 (g/mol H2)
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
Balanced equation. Mg + H2SO4 -> MgSO4 + H2 ------------------------------------- ( sufuric acid in excess---magnesium limits, drives reaction ) 24 grams magnesium (1 mole Mg/24.31 g)(1 mole H2/1 mole Mg)(2.016 g/1 mole H2) = 1.9 grams of hydrogen gas produced ( can call it 2.0 grams ) --------------------------------------------------
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
1 mol of hydrogen molecule = 1 mol of H2 = molar mass of H2 = 2.0gmol-1 2.0gmol-1 x 1mol = 2.0g 1 mol of hydrogen atom = 1 mol of H = molar mass of H = 1.0gmol-1 1.0gmol-1 x 1mol = 1.0g Hence, they have different masses
Do you mean this reaction? Zn + 2HCl -> ZnCl2 + H2 I will assume zinc is limiting. 50 grams Zn (1 mole Zn/65.41 grams)(1 mole H2/1 mole Zn)(2.016 grams/1 mole H2) = 1.5 grams of hydrogen gas
Hydrogen gas is H2. 1 moles H2 has a molar mass of 2.0158. Thus, 4 moles H2 gas has a mass of2.0158 g/mole x 4 moles = 8.063 g
For H2 (natural occurring element Hydrogen) it is 2*1.00794 a.m.u = 2.01588 a.m.eThis means that 1.00000 mole H2 has a mass of 2.01588 grams
I assume you mean excess hydrochloric acid. Balanced equation. 2Al + 6HCl = 2AlCl3 + 3H2 2.70 grams Al (1 mole Al/26.98 grams)(3 mole H2/2 mole Al)(2.016 grams/1 mole H2) = 0.303 grams hydrogen gas produced --------------------------------------------------