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Balanced equation first.

2H2 + O2 --> 2H2O

Get moles products.

4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H2

64 grams O2 (1 mole O2/32 grams) = 2.000 moles O2

I suspect hydrogen gas of limiting and driving the reaction.

1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )

2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )

1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)

= 36 grams water produced

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Q: What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?
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